xy-y²分之y√x+x√y-x√x-y√y分之x+√xy+y 注：√是根号,这题答案是√y分之1

xy-y²分之y√x+x√y-x√x-y√y分之x+√xy+y 注：√是根号,这题答案是√y分之1
xy-y²分之y√x+x√y-x√x-y√y分之x+√xy+y 注：√是根号,这题答案是√y分之1

xy-y²分之y√x+x√y-x√x-y√y分之x+√xy+y 注：√是根号,这题答案是√y分之1
原式=(y√x+x√y)/(xy-y²)-(x+√xy+y)/(x√x-y√y)
=(y√x+x√y)/[y(x-y)]-[(x+√xy+y)(x√x+y√y)]/[(x√x-y√y)(x√x+y√y)]
=(y√x+x√y)/[y(x-y)]-(x²√x+xy√y+x²√y+y²√x+xy√x+y²√y)/(x³-y³)
=(y√x+x√y)/[y(x-y)]-[(x²√x+xy√x+y²√x)+(x²√y+xy√y+y²√y)]/[(x-y)(x²+xy+y²)]
=(y√x+x√y)/[y(x-y)]-[√x(x²+xy+y²)+√y(x²+xy+y²)]/[(x-y)(x²+xy+y²)]
=(y√x+x√y)/[y(x-y)]-[(x²+xy+y²)(√x+√y)]/[(x-y)(x²+xy+y²)]
=(y√x+x√y)/[y(x-y)]-(√x+√y)/(x-y)
=(y√x+x√y)/[y(x-y)]-[y(√x+√y)]/[y(x-y)]
=(y√x+x√y-y√x-y√y)/[y(x-y)]
=(x√y-y√y)/[y(x-y)]
=[√y(x-y)]/[y(x-y)]
=(√y)/y [1/√y=(√y)/y]