A spring(k=400N/m)is hung vertically.a) if a 5kg mass is attached to the end if the spring and gently lowered to rest position,what will be the stretch of the spring?b) if the 5kg mass is attached and simply dropped,what will be the maximum velocit

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Aspring(k=400N/m)ishungvertically.a)ifa5kgmassisattachedtotheendifthespringandgentlyloweredtorestpos

A spring(k=400N/m)is hung vertically.a) if a 5kg mass is attached to the end if the spring and gently lowered to rest position,what will be the stretch of the spring?b) if the 5kg mass is attached and simply dropped,what will be the maximum velocit
A spring(k=400N/m)is hung vertically.a) if a 5kg mass is attached to the end if the spring and gently lowered to rest position,what will be the stretch of the spring?b) if the 5kg mass is attached and simply dropped,what will be the maximum velocity and fhe maximum stretch?

A spring(k=400N/m)is hung vertically.a) if a 5kg mass is attached to the end if the spring and gently lowered to rest position,what will be the stretch of the spring?b) if the 5kg mass is attached and simply dropped,what will be the maximum velocit
第一问:
根据胡克定律 F=x*k F=5*9.81=49.05N
X=F/k=49.05/400=0.123m 因此 第一问的形变是0.123米
第二问:
显然由第一问得出 当形变是0.123米时 弹力和重力首次持平 此时正向加速度为0 因此速度也为最大值
由能量守恒定律可知 1/2mv0²+mgh=1/2mvt²+1/2kx²
上式中 mgh=49.05*0.123=6.03315J
1/2kx²=0.5*400*0.123²=3.0258J
所以可知 1/2mvt²=6.00315-3.0258=3.00735J
vt=1.097m/s
最大形变 当末速度首次为0时 为最大形变
由能量守恒可知
mgh=1/2kh² 解得h=2mg/k=0.24525m

此题用能量守恒的方法 不考虑加速度的中间变化过程
关键是分析什么时刻速度最大 什么时刻形变最大
希望能帮到你

A spring(k=400N/m)is hung vertically.a) if a 5kg mass is attached to the end if the spring and gently lowered to rest position,what will be the stretch of the spring?b) if the 5kg mass is attached and simply dropped,what will be the maximum velocit Spring Festival is a n----- holiday 首字母填空 k=m>n?n: log(a^k)(M^n)=(n/k)log(a)(M) (n∈R)怎么证明请不要用换底公式 #include main() { int m,i,k; scanf(%d,&m); k=sqrt(m); for(i=2;i=k+1)printf(%d is a prime number ,m);elseprintf(%d is not a prime number ,m);getch();}这个程序是判断一个数是不是素数,在 for 语句中i=k+1 A mass m is attached to a massless spring with a force constant k.The mass rests on a horizontal frictionless surface.The system is compressed a distance x from the spring's initial position and the released.The momentum of the mass when the spring p 已知m(b+c)=n(c+a)=k(a+b),且mnk不等于0.求证:(b-c)/(m(n-k))=(c-a)/(n(k-m))=(a-b)/(k(m-n)) 程序提示:The expression to the left of the equals sign is not a valid target for an assignment.程序如下:function y=K(k)%program to compute the complete eliptic integrals K(k)%Using the arith-geom mean method[m n]= size(k);if m+ n= =2K=[k 已知k=m-a/n-a(k≠1).则a= 对一棵满二叉树,m个树叶,k个分枝节点,n个节点.则:( )A、n=k+m B、 k+m=2n C、m=k-1 D、n=2k-1; 关于弹簧简谐运动的物理问题.怎么在碰撞后求振幅?翻译见下A 2.00-kg object is attached to an ideal massless horizontal spring of spring constant 100.0 N/m and is at rest on a frictionless horizontal table.The spring is aligned a 判断一个数是否是素数的程序讲解main(){int m,i,k;scanf(%d,&m);k=sqrt(m);for(i=2;i=k+1)printf(%d is a prime number ,m);elseprintf(%d is not a prime number ,m);}不懂啊,高人请细讲一下吧 一道C语言 选择题当K的值不为0时,在下列选项中能够将K的值赋给变量m,n的是:A> m=k=n; B>(m=k)&&(n=k); C>(m=k)||(n=k);D>(k=m)&&(n=k) 集合M={a|a=kπ+π/6,k属于Z},N={b|2kπ A:B=M:N,B:C=N:K,那么A:B:C=__________ 如果 a:b=m:n,b:c=n:k那么a:b:c=? 如果a:b=m:n,b:c=n:k,那么,a:b:c=( 已知a:b=m:n,b:c=n:k(k≠0),那么a:b:c=k分之m:___:___