（3x/2 √x/y - 2/5 √3/xy + 1/3 √xy/2 ) ÷ x/2 √ x/y（3x/2 √x/y - 2/5 √3/xy + 1/3 √xy/2 ) ÷ x/2 √ x/y 我要完整的解题公式.

若x>0,y>0,且√x(√x+√y)=3√y(√x+5√y),求2x+2√x*√y+3y/x-√x*√y+y y=(3x^2-x√x+5√x-9)/√x 求导 化简:5(x-y)+2(x+y)-3(x-y) √x(√x+2√y)=√y(6√x+5√y,求x-3√xy+2y/x+√xy-6y 先化简 再求值 (2x-y)(y+x)-(x-2y)(2y+x)-(-3y+x)^2其(√x+1)+y^2+4=-4y 已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y) (2x+y)²+(x+3y)(x-3y)-x(5x+8y)因式分解 xy²/(x²y-y) × x²/(x²+x)=(x²-3x)/(x²-5x) × 2x-10/(x²-6x+9)=化简求植x²-1/(x²-x-2)除以x/2x-4,其中x=1/2[x-x/(x+1)]除以[x/(2x-4)] ,其中x=√2+1 (2x-3y)-(5x-y) (2X-3y)-(5x-y) (2x-5y)(3x+y) 已知4x²+y²-4x-6y+10=0求（2/3x（√9x）+(y²√x/y³)×(x²√1/x×5x√y/x)的值 已知4x²+y²-4x-6y+10=0求（2/3x（√9x）+(y²√x/y³)-(x²√1/x-5x√y/x)的值 已知4x²+y²-4x-6y+10=0,求[(2/3)x√(9x)+y²√(x/y³)-(x²√(1/x)-5x√(y/x)的值 因式分解(x-2y)(x-3y)+(x-4y)(x-5y)+（x-3y)(x-5y)+(x-2y)(x-4y) x(x-y)2-(y-x)3 y=(3x-1)/(x+1) (x>=5)值域 y=x-√(1-2x)值域 [2/3x-2/x+y(x+y/3x-x-y)]/x-y/x