#include int f1(int a,int b)15,9 { int c; c=b%2; return a+c; }int f2(int a,int b){ int c;a+=a;b+=b;c=f1(a+b=14,++b9);return c;}void main(){ int a=3,b=4;cout
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#includeintf1(inta,intb)15,9{intc;c=b%2;returna+c;}intf2(inta,intb){intc;a+=a;b+=b;c=f1(a+b=14,++b9)
#include int f1(int a,int b)15,9 { int c; c=b%2; return a+c; }int f2(int a,int b){ int c;a+=a;b+=b;c=f1(a+b=14,++b9);return c;}void main(){ int a=3,b=4;cout
#include int f1(int a,int b)15,9 { int c; c=b%2; return a+c; }
int f2(int a,int b)
{ int c;
a+=a;b+=b;
c=f1(a+b=14,++b9);
return c;
}
void main()
{ int a=3,b=4;
cout
#include int f1(int a,int b)15,9 { int c; c=b%2; return a+c; }int f2(int a,int b){ int c;a+=a;b+=b;c=f1(a+b=14,++b9);return c;}void main(){ int a=3,b=4;cout
#include //C++头文件
using namespace std;
int f1(int a,int b)//15,9删除
{
int c;
c=b%2;
return a+c;
}
int f2(int a,int b)
{ int c;
a+=a;b+=b;
c=f1(a+b=14,++b9);
return c;
}
int main()//int类型,C++
{ int a=3,b=4;
cout
#include int main( ){int c;cout
#include sub(int *a,int n,int k) { if(k
#include void main( ) { int a=3,b=5; int *p,*q; void f1(int x,int y);void f2(int *x,int *y);p=&a; q=&b;f1(*p,*q) ;printf(a=%d ,b=%d
,a,b);f2(p,q);printf(a=%d ,b=%d
,a,b);}void f1(int x,int y) { int t;t=x; x=y; y=t;}void f2(int *x,int *y) { int
#include int f1(int a,int b)15,9 { int c; c=b%2; return a+c; }int f2(int a,int b){ int c;a+=a;b+=b;c=f1(a+b=14,++b9);return c;}void main(){ int a=3,b=4;cout
int
C++有道题看不懂,#include int func(int a,int b);int main(){cout
#include int inc(int a) { return(++a); } int multi(int*a,int*b,int*c) { return(*c=*a**b); } typedef int(FUNC1)(int in); typedef int(FUNC2) (int*,int*,int*); void show(FUNC2 fu
#include void modify(int x,int y) {cout
实在看不懂#include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include using namespace std;int cases;int main() {double cl = clock();scanf(%d,
C++中计算Fibonacci数列,就是兔子问题,我想问下怎么理解这个程序,#include #include using namespace std;int main(){long f1,f2;int i;f1=f2=1;for(i=1;i
#include int fun(int n,int *s){int f1,f2;if(n==1IIn==2)*s=1;else{fun(n-1,&f1);fun(n-2,&f2);*s=f1+f2;} return 0;void main(){int x;fun(6,&x);printf(%d
,x);}这个题的求解过程详解
#include int fun(int n,int *s){int f1,f2;if(n==1IIn==2)*s=1;else{fun(n-1,&f1);fun(n-2,&f2);*s=f1+f2;} return 0;void main(){int x;fun(6,&x);printf(%d
,x);}不会,完全看不懂.标记下.
#include main() { int f,f1,f2,i; f1= 0;f2 =1; printf(%d %d ,f1,f2); for(i=3;i
#include stdio.h double fun(int m) { // }
运行vc++时 #include int main() { cout
#include using namespace std; int main() { cout
C++计算阶乘n#include #include #include #include using namespace std;int main(){int sum = 1,d;int n;cin >> n;for(int i=1;i
一道C语言题,# include int fun (int n,int *s){int f1,f2;if (n==1||n==2) *s=1;else {fun(n-1,&f1); /* fun(5,&f1) fun(4,&f1) fun(3,&f1) fun(2,&f1) */fun(n-2,&f2); /* fun(4,&f2) fun(2,&f2) */*s=f1+f2;}}main(){int x;fun(6,&x);printf (
%d
,x);}输