1.解方程:(x+1)/(x-1)-(4/(x^2-1))=12.公路全长s千米,某人步行t小时可以到达.为了提前半小时到达,则他每小时应多走多少千米?3.计算:(1+(1/x-1))((x/x+1)-1)÷(1+(x^2/1-x^2))

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1.解方程:(x+1)/(x-1)-(4/(x^2-1))=12.公路全长s千米,某人步行t小时可以到达.为了提前半小时到达,则他每小时应多走多少千米?3.计算:(1+(1/x-1))((x/x+1)

1.解方程:(x+1)/(x-1)-(4/(x^2-1))=12.公路全长s千米,某人步行t小时可以到达.为了提前半小时到达,则他每小时应多走多少千米?3.计算:(1+(1/x-1))((x/x+1)-1)÷(1+(x^2/1-x^2))
1.解方程:(x+1)/(x-1)-(4/(x^2-1))=1
2.公路全长s千米,某人步行t小时可以到达.为了提前半小时到达,则他每小时应多走多少千米?
3.计算:(1+(1/x-1))((x/x+1)-1)÷(1+(x^2/1-x^2))

1.解方程:(x+1)/(x-1)-(4/(x^2-1))=12.公路全长s千米,某人步行t小时可以到达.为了提前半小时到达,则他每小时应多走多少千米?3.计算:(1+(1/x-1))((x/x+1)-1)÷(1+(x^2/1-x^2))
1. 当X不等于1时,两边乘以X^2-1
得出(x+1)^2-4=x^2-1
x=1
与假设不符,所以无解.
2 V=S/(T-0.5)
3 原式=X/(X-1)(-1/X+1)÷(1+(x^2/1-x^2))
=-X/(X^2-1)÷1/(1-x^2)
=X