x1+x2+x3=y1+y2+y3=x1y1+x2y2+x3y3=0,求x1^2/(x1^2+x2^2+x3^2)+y1^2/(y1^2+y2^2+y3^2)的取值范围
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x1+x2+x3=y1+y2+y3=x1y1+x2y2+x3y3=0,求x1^2/(x1^2+x2^2+x3^2)+y1^2/(y1^2+y2^2+y3^2)的取值范围x1+x2+x3=y1+y2+y
x1+x2+x3=y1+y2+y3=x1y1+x2y2+x3y3=0,求x1^2/(x1^2+x2^2+x3^2)+y1^2/(y1^2+y2^2+y3^2)的取值范围
x1+x2+x3=y1+y2+y3=x1y1+x2y2+x3y3=0,求x1^2/(x1^2+x2^2+x3^2)+y1^2/(y1^2+y2^2+y3^2)的取值范围
x1+x2+x3=y1+y2+y3=x1y1+x2y2+x3y3=0,求x1^2/(x1^2+x2^2+x3^2)+y1^2/(y1^2+y2^2+y3^2)的取值范围
参考答案\x09坚持做你自己,而不是被别人修改的面目全非.
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matlab如何将一组数代入原方程的字母里?syms x1 x2 x3 x4 y1 y2 y3 y4 X1 X2 X3 X4 Y1 Y2 Y3 Y4A=[x1,y1,1,0,0,0,-x1*X1,-y1*X1;0,0,0,x1,y1,1,-x1*Y1,-y1*Y1;x2,y2,1,0,0,0,...-x2*X2,-y2*X2;0,0,0,x2,y2,1,-x2*Y2,-y2*Y2;x3,y3,1,0,0,0,-x3*X3,-y3*X3;
MATLAB 已知3点求夹角>> x1=1;y1=1;x2=0;y2=0;x3=0;y3=3;theta=acosd(dot([x1-x2,y1-y2],[x3-x2,y3-y2])/(norm([x1-x2,y1-y2])*norm([x1-x2,y3-y2])))theta =47.8696>> x1=1;y1=1;x2=0;y2=0;x3=0;y3=3;theta=acos(dot([x1-x2,y1-y2],[x3-x2,y3-y2])/(norm([x1-x2,
点(x1,y1),(x2,y2),(x3,y3)其中x1
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x1+x2+x3=y1+y2+y3=x1y1+x2y2+x3y3=0,求x1^2/(x1^2+x2^2+x3^2)+y1^2/(y1^2+y2^2+y3^2)的取值范围
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lingo线性规划请问这个模型对吗?是线性规划吗?我是个菜鸟MaxGDP=0.6734X1+0.2536X2+0.4733X3;0.1315X1+0.0260X2+0.0069X3+Y1=X1;0.1774X1+0.6231X2+0.2322X3+Y2=X2;0.0177X1+0.0973X2+0.2876X3+Y3=X3;Y1/X1>=0.3346;Y2/X2>=0.1555;Y3/X3>=
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关于一个简单的线性变换已知X1=2y1+2y2+y3x2=3y1+y2+5y3x3=3y1+2y2+3y3求x1 x2 x3 到y1 y2 y3 的线性变换需解答过程