(1+2/5+1/2÷3/4)×2/7 用简便方法解答
来源:学生作业帮助网 编辑:六六作业网 时间:2025/01/31 06:52:13
(1+2/5+1/2÷3/4)×2/7用简便方法解答(1+2/5+1/2÷3/4)×2/7用简便方法解答(1+2/5+1/2÷3/4)×2/7用简便方法解答(1+2/5+1/2×4/3)×2/7
(1+2/5+1/2÷3/4)×2/7 用简便方法解答
(1+2/5+1/2÷3/4)×2/7 用简便方法解答
(1+2/5+1/2÷3/4)×2/7 用简便方法解答
(1+2/5+1/2×4/3)×2/7
2÷4/3 4/7÷6/7 8/7×5 1/3-1/5 7/15÷10%
5/7÷[1÷(2/3-1/5)]
5/28÷(4/7-1/2)
1:1/5×[1/3÷(1/2+5/6)] 2:1-(1/6×2/5)÷7/9 3:12÷(1-31:1/5×[1/3÷(1/2+5/6)]2:1-(1/6×2/5)÷7/93:12÷(1-3/7)4:4/5×2/3-1/6÷1/25:(1/2+1/3)÷(1-3/8)6:[(1-3/5)×2/3]÷4
1/40×【6/7÷(3/4+2/5)】
记集合T={0,1,2,3,4,5,6},M={a1÷7+a2÷7^2+a3÷7^3+a4÷7^4∣ai∈T,i=1,2,3,4},将M中的元素按从大到小的顺序排列,则第2005个数是() A.5÷7+5÷7^2+6÷7^3+3÷7^4 B.5÷7+5÷7^2+6÷7^3+2÷7^4 C.1÷7+1÷7^2+0÷7^3+4÷7^4 D.1÷7+1÷7^2
记集合T={0,1,2,3,4,5,6},M={a1÷7+a2÷7^2+a3÷7^3+a4÷7^4∣ai∈T,i=1,2,3,4},将M中的元素按从大到小的顺序排列,则第2005个数是() A.5÷7+5÷7^2+6÷7^3+3÷7^4 B.5÷7+5÷7^2+6÷7^3+2÷7^4 C.1÷7+1÷7^2+0÷7^3+4÷7^4 D.1÷7+1÷7^2
先求商,再观察 1÷7 2÷7 3÷7 4÷7 5÷7 6÷7
1÷7= 2÷7= 3÷7= 4÷7= 5÷7= 6÷7= 要小数的
4^2÷(-1/4)-5^4÷(-5)^3,
能简算的要简算 1、2/3×5/7+2/3×2/72、7/2×3/7÷6 3、8×5/6+2/5÷4 4、(1/2+2/5)÷3/2
1/5×12÷1/5= 0.25×12.5÷1/32= 2/3×4/9×1/5×12÷1/5= 0.25×12.5÷1/32=2/3×4/9×1/2=6.9+3.1-6.9+3.1=1÷1/2-1/2÷1=3/5+3/5÷3/5+3/5=1÷1/7×1÷1/7=4/5×4/5÷4/5×4/5=
[-24^4-(-2^5)+(-24)^4]*[-(2/3)÷1(7/8)*-(1/4)*4.5-6^2]÷32
1÷(2÷3)÷(3÷4)÷(4÷5)怎么做
2u÷3+3v÷4=1÷2 4u÷5+5v÷6=7÷15 用代入法
18÷7/6+6x1/7+16/7÷1/6 (4又5分之3+3又7分之2)÷(2/5+2/7)
(12又2分之1+1又3分之2÷4)-7分之5×7
(1+2/5+1/2÷3/4)×2/7 用简便方法解答