因式分解x4-7x2y2+81y4

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因式分解x4-7x2y2+81y4因式分解x4-7x2y2+81y4因式分解x4-7x2y2+81y4x4-7x2y2+81y4=x4+18x2y2+81y4-25x2y2=(x²+9y&#

因式分解x4-7x2y2+81y4
因式分解x4-7x2y2+81y4

因式分解x4-7x2y2+81y4
x4-7x2y2+81y4
=x4+18x2y2+81y4-25x2y2
=(x²+9y²)²-（5xy）²
=(x²+9y²+5xy)(x²+9y²-5xy)

x^4-7x^2*y^2+81y^4
=(x^4+18x^2*y^2+81y^4)-25x^2*y^2
=(x^2+9y^2)-(5xy)^2
=(x^2+5xy+9y^2)(x^2-5xy+9y^2)

因式分解x4-7x2y2+81y4 x4-7x2y2+9y4因式分解 4x4+5x2y2+7xy3+2y4怎么因式分解? 因式分解,x4-7x2y2+y4=?x4-7x2y2+y4=?应该是(x2+?xy+y2)(x2-?xy+y2) 的形式,那个?是多少因式分解：x4+y4+z4-2x2y2-2y2z2+2z2x2 因式分解x4+y4+z4-2x2y2-2x2z2-2y2z2x,y,后的2为平方. 因式分解：x4+y4+z4-2x2y2-2y2z2-2z2x2 最好能有详细过程,谢谢 x4+y4因式分解 x4次方-y4次方因式分解 x4-2x4y4+y4因式分解因式分解 x5n+xn+1 2a2-a2b+(b-2)(ab-a)2 x5+x4+x3+x2+x+1 x4+y4-2x2y2-2x2-2y2+1 x4次方+1/4y4次方因式分解因式分解x4+3x平方y+y4 因式分解:1.x5+x4+12 2.(ax+by)2+(bx-ay)2 3.x3-3x2+4 4.(x+y)2-4(x+y-1) 5.p的m+3次方-p的m次方6.3x4-7x2y2+3y4 7.ab(c2+d2）+cd(a2+b2)第一题打错了，应该是x5+x4+1 证明;x4+y4+z4-2x2y2-2x2y2-2y2z2能被（x+y+z）整除已知：x-y+1=0,xy-2x-2y-7=0,求x2+y2以及4x2y2-x4-y4. 多项式相除问题(x6 + x5y – xy5 – y6):(x4 + x3y + x2y2 + xy3 + y4) 谁会因式分解呀 1.x4-12x+3232.x4+7x3+14x2+7x+13.x4-11x2y2+y24.(x+3)(x2-1)(x+5)-20