4x∧2+y∧2-4x-6y+10=0 （初二数学）求x和y的值

x^2+4y^2-6x+4y+10=0,求x^4-y^4/(x+2y)(x-2y)*x+2y/xy^2+y^3除以（x^2+y^2/y)^2的值 已知实数x, y满足x²+y²-2x+6y+10=0,求y∧-x. 已知：4x^2+y^2-4x-6y+10=0,求y/x-x/y的值 已知2x-y=10 求代数式[(x∧2+y∧2)-(x-y)∧2+2y(x-y)]÷4y的值 已知x^2+y^2+13-4x+6y=0,求(2x-y)^2-2(2x-y)(x+2y)+(x+2y)^2 已知x^2+y^2-2x-6y+10=0,求4(x^2+y)(x^2-y)-(2x^2-y)^2 x²+y²-2x-6y+10=0,求4(x²+y)(x²-y)-(2x²-y)² 已知x²+y²-2x-6y+10=0,求4(x²+y)(x²-y)-(2x²-y)² {3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1 （x+y）/2- x-y/2=6 3(x+y)=4(x-y) x+y/3+x-y/2=6 4(x+y)-2(x-y)=40 x*x+2x+y*y-4y+5=0 x= y= x+y/2+x-y/3=6,4(x+y)-3(x-y)=-20 {(x+y)/2+(x-y)/3=6 4(x+y)-3(x-y)=-20 4(x+y)-3(x-y)=-20,2/x+y+3/x-y=6 x^2+6x+y^2+4x+10=0,则x+y等于多少? {4x-3y-10=0 3x-2y=0,{3x-4(x-y)=2 2x-3y=1,{2(x+y)-(x-y)=3 (x+y)-2(x-y)=1 已知x.x+y.y+8x+6y+25=0,求代数式(x.x-4y.y)/(x.x+4xy+4y.y)-x/(x+2y)的值