x+y/3+x-y/2=6 4(x+y)-2(x-y)=40

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x+y/3+x-y/2=64(x+y)-2(x-y)=40x+y/3+x-y/2=64(x+y)-2(x-y)=40x+y/3+x-y/2=64(x+y)-2(x-y)=40答:(x+y)/3+(x-

x+y/3+x-y/2=6 4(x+y)-2(x-y)=40
x+y/3+x-y/2=6 4(x+y)-2(x-y)=40

x+y/3+x-y/2=6 4(x+y)-2(x-y)=40
答:
(x+y)/3+(x-y)/2=6
4(x+y)-2(x-y)=40
整理得:
2(x+y)+3(x-y)=36
2(x+y)-(x-y)=20
两式相减得:
4(x-y)=16
x-y=4
代入得:2(x+y)-4=20
x+y=12
结合x-y=4解得:
x=8,y=4

(x+y)/3+(x-y)/2=6,①
4(x+y)-2(x-y)=40,②
①*4+②,(16/3)(x+y)=64,x+y=12,③
①*12-②,14(x-y)=32,x-y=16/7.④
(③+④)/2,x=50/7,
(③-④)/2,y=34/7.
∴{x=50/7,
{y=34/7.
希望能解决您的问题。

令x+y=u, x-y=v
所以原方程变为
2u+3v=36
4u-2v=40
解得
u=12
v=4
所以x+y=12
x-y=4
解得x=8, y=4

x,y=8或4