3^x=12^y=8,1/x+1/y=?
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3^x=12^y=8,1/x+1/y=?3^x=12^y=8,1/x+1/y=?3^x=12^y=8,1/x+1/y=?先解出x=log以3为底8的对数,y=log12为底8的对数所以1/x+1/y=
3^x=12^y=8,1/x+1/y=?
3^x=12^y=8,1/x+1/y=?
3^x=12^y=8,1/x+1/y=?
先解出x=log以3为底8的对数,y=log12为底8的对数 所以1/x+1/y=log以8为底3的对数,y=log8为底12的对数=log8为底36的对数
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已知x^2+y^2-8x+12y+52=0 ,求1/2x-1/x-y(x-y/2x-x^2+y^2)
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