化简[sin(π-α)tan(5π/2+α)]/[cos(2π-α)cot(π/2-α)]分后给

若a属于(0,π/2)试比较tanα、tan(tanα)、tan(sinα) 1.求证tanαsinα/tanα-sinα=tanα+sinα/tanαsinα2.已知sinα+cosα=-1/5(π/2 化简cos2(-α)-tan(2π+α)/sin(-α) 化简:(sin(α-3π)*cos(-α))/(tan(α-5π)*cos^2(α-5π)*tan(4π-α)) 化简cos(α -π )tan(α-2π)tan(2π-α)/sin(π+α) cos(π-α)tan(2π-α)tan(π-α)/sin(π+α) 化简 化简[sin(π-α)cos(3π-α)tan(-α-π)]/[tan(4π-α)sin(5π+α)] 化简sin(2π-α）tan（α+π）tan（-α-π）/ 化简sin(3π-α)/[sin(-α-2π)]+cos(4π-α)/[cos(α-5π)]+tan(-α)/[tan(π+α)] 化简[tan(2π-α)sin(-2π-α)cos(6π-α)]/[cos(α-π)sin(5π-α)] 化简tan(2π-α)sin(-2π-α)cos(6π-α)/cos(α-π)sin(5π-α) 化简:cos(2π-α)sin(-π-α)/sin(π/2+α)tan(3π-α) 化简cos(α-π)cot(5π-α)/tan(2π-α)sin(-2π-α) 化简sin(-a-5π)sin(a-π/2)-tan(a-3π/2)tan(2π-a)第二个sin改成cos 化简2tan(-α).cos(7π-α)/sin(5π-α) 已知3sinα+5cosα=5,求3cosα-5sinα第二题 化简 根号[1-2tan(-37π/6)+tan²(-43π/6)]第三题 已知 [1-tan(π-α)]/[1-tan(π+α)=3+2根号2 求cos²(π-α)+sin(π+α)cos(π-α)+2sin²（α-π） 化简[sin²(α+π)cos(α+π)]/tan(α+π)cos³(-α-π)tan(-α-2π)化简sin²(α+π)cos(α+π)/tan(α+π)cos³(-α-π)tan(-α-2π) 化简cos(α-π)sin²(α+2π)/tan (α+4π)tan(α+π)cos³(-α-π)