化简sin(2π-α)tan(α+π)tan(-α-π)/
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/08 16:41:03
化简sin(2π-α)tan(α+π)tan(-α-π)/化简sin(2π-α)tan(α+π)tan(-α-π)/化简sin(2π-α)tan(α+π)tan(-α-π)/原式=(-sina)tan
化简sin(2π-α)tan(α+π)tan(-α-π)/
化简sin(2π-α)tan(α+π)tan(-α-π)/
化简sin(2π-α)tan(α+π)tan(-α-π)/
原式=(-sina)tana(-tana)/(-cosa)(-tana)=tan²α
化简sin(2π-α)tan(α+π)tan(-α-π)/
已知tanα-tanβ=2tanα^2tanβ,且αβ均不等于kπ/2.试求sinβsin(2α+β)/sinβ或者能给思路已知就是这个:tanα-tanβ=2tanαtanαtanβ
若a属于(0,π/2)试比较tanα、tan(tanα)、tan(sinα)
化简sin(9π+α)tan(3/2π+α)/cos(-4π-α)tan(15π+α)tan(7/2π-α)
若f(α)=[sin(π-α)cos(2π-α)tan(-α+π)]/[-tan(-α-π)sin(-π-α)]化简
[sin(2π+α)·tan(-α)·cos(-α)]÷[sin(-α)·cos(2π+α)·tan(2π+α)化简
已知α∈(0,π|2),2tanα+3sinβ=7,且tanα-6sinβ=1,求sinα的值
化简sin(π+α)/cos(-α)tan(2π-α)等于什么?
化简:sin²(α+π)cos(-α+π)/tan(α+π)tan(α+2π)cos²(-α-π)1.cos(27°+α)cos(33°-α)-sin(27°+α)sin(33°-α) 2.sin²(α+π)cos(-α+π)/tan(α+π)tan(α+2π)cos²(-α-π)
化简sin³(﹣α)cos(2π+α)tan(2π-α)/sin(α-2π)cos(α-3π/2)-tan(π-α)tan(3π/2-α)
已知3sinα+5cosα=5,求3cosα-5sinα第二题 化简 根号[1-2tan(-37π/6)+tan²(-43π/6)]第三题 已知 [1-tan(π-α)]/[1-tan(π+α)=3+2根号2 求cos²(π-α)+sin(π+α)cos(π-α)+2sin²(α-π)
化简cos2(-α)-tan(2π+α)/sin(-α)
若α∈(-π/2+2kπ,2kπ)(k∈Z),则sinα,cosα,tanα的大小关系是A.tanα>sinα>cosαB.tanα>cosα>sinαC.tanα<sinα<cosαD.tanα<cosα<sinα
化简cos(α -π )tan(α-2π)tan(2π-α)/sin(π+α)
cos(π-α)tan(2π-α)tan(π-α)/sin(π+α) 化简
①sin(α+180°)cos(-α)sin(-α-180°)和②sin³(-α)cos(2π+α)tan(-α-π)化简
1)tan(x/2+π/4)+tan(x/2-π/4)=2tanx(2)(1-2sinαcosα/cos²α-sin²α)=(1-tanα)/(1+tanα)
已知5sinβ=sin(2α+β),求tan(α+β)/tanα