tan(π/12)+1/tan(π/12)=啥?
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tan(π/12)+1/tan(π/12)=啥?tan(π/12)+1/tan(π/12)=啥?tan(π/12)+1/tan(π/12)=啥?tan(π/12)+1/tan(π/12)=sin(π/
tan(π/12)+1/tan(π/12)=啥?
tan(π/12)+1/tan(π/12)=啥?
tan(π/12)+1/tan(π/12)=啥?
tan(π/12)+1/tan(π/12)
=sin(π/12)/cos(π/12)+cos(π/12)/sin(π/12)
=[sin(π/12)的平方+cos(π/12)的平方]/sin(π/12)cos(π/12)
=1/sin(π/12)cos(π/12)
=2/2sin(π/12)cos(π/12)
=2/sin(π/6)
=4
tan(π/12)-(1/tan(π/12))
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计算 tanπ/12+1/tanπ/12
计算tanπ/12 / (1-tan^2π/12)=
tan(π/12)+1/tan(π/12)=啥?
tanπ/12-1/tanπ/12=
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