tan(π/12)+1/tan(π/12)=啥?

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tan(π/12)+1/tan(π/12)=啥?tan(π/12)+1/tan(π/12)=啥?tan(π/12)+1/tan(π/12)=啥?tan(π/12)+1/tan(π/12)=sin(π/

tan(π/12)+1/tan(π/12)=啥?
tan(π/12)+1/tan(π/12)=啥?

tan(π/12)+1/tan(π/12)=啥?
tan(π/12)+1/tan(π/12)
=sin(π/12)/cos(π/12)+cos(π/12)/sin(π/12)
=[sin(π/12)的平方+cos(π/12)的平方]/sin(π/12)cos(π/12)
=1/sin(π/12)cos(π/12)
=2/2sin(π/12)cos(π/12)
=2/sin(π/6)
=4