Assume that p is a polynomial function on the set of real numbers.If p(0)=p(2)=3 and p'(0)=p'(2)=-1,then ∫(0,2)xp''(x)dx=?(a)-3(b)-2(c)-1(d)1(e)2
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Assumethatpisapolynomialfunctiononthesetofrealnumbers.Ifp(0)=p(2)=3andp''(0)=p''(2)=-1,then∫(0,2)xp''''(
Assume that p is a polynomial function on the set of real numbers.If p(0)=p(2)=3 and p'(0)=p'(2)=-1,then ∫(0,2)xp''(x)dx=?(a)-3(b)-2(c)-1(d)1(e)2
Assume that p is a polynomial function on the set of real numbers.If p(0)=p(2)=3 and p'(0)=p'(2)=-1,then ∫(0,2)xp''(x)dx=?
(a)-3(b)-2(c)-1(d)1(e)2
Assume that p is a polynomial function on the set of real numbers.If p(0)=p(2)=3 and p'(0)=p'(2)=-1,then ∫(0,2)xp''(x)dx=?(a)-3(b)-2(c)-1(d)1(e)2
利用分步积分法:∫(0,2)xp''(x)dx=∫(0,2)xd(p'(x))=[xp'(x)]''上限x=2,下限x=0''-∫(0,2)p'(x)dx=2p'(2)-0-[P(2)-P(0)]=-2
Assume that p is a polynomial function on the set of real numbers.If p(0)=p(2)=3 and p'(0)=p'(2)=-1,then ∫(0,2)xp''(x)dx=?(a)-3(b)-2(c)-1(d)1(e)2
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