cos*π/12—sin*π/12
来源：学生作业帮助网 编辑：六六作业网 时间：2024/12/20 01:34:59
cos*π/12—sin*π/12cos*π/12—sin*π/12cos*π/12—sin*π/12原式=根号2*(根号2/2*cosπ/12—根号2/2*sinπ/12)=根号2*(sinπ/4c
cos*π/12—sin*π/12
cos*π/12—sin*π/12
cos*π/12—sin*π/12
原式 = 根号2 * (根号2/2 * cosπ/12—根号2/2 * sinπ/12 )
= 根号2 * (sinπ/4cosπ/12—cosπ/4sinπ/12)
=根号2 * sin(π/4-π/12)
=根号2 * sin(π/6)
=根号2/2
cos*π/12—sin*π/12
（sinπ/24)(cosπ/24)(cosπ/12)
（sinπ/24)(cosπ/24)(cosπ/12)
sinπ/12*cosπ/12=?
求值：sin(π/12)+cos(π/12)
sin(π/12)-cos(π/12)=
cosπ／12乘以sinπ／12
计算cosπ/12*sinπ/12
（cosπ/12-sinπ/12)*(COSπ/12+sinπ/12)等于
(cosπ/12 -sinπ/12)(cosπ/12 +sinπ/12)等于
（cosπ/12-sinπ/12)(cosπ/12+sinπ/12)的值为
（cosπ/12 -sinπ/12）（cosπ/12 +sinπ/12）=
(sinπ/12+cosπ/12)(sinπ/12-cosπ/12)=
已知α=7/12π,那么cosα√（1-sinα）/(1+sinα)+sinα√（1-cosα）/(1-cosα)=
cos^2π/12-sin^2π/12等于
sin(π/12)cos(π/12)的值
求sin π/12-(根号3)cos π/12
cosπ/12+(根号3)×sinπ/12的值