sin(5л+A)=(m-3)/(m+5).cos(3л-a)=(4-2m)/(m+5)求实数M的值
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sin(5л+A)=(m-3)/(m+5).cos(3л-a)=(4-2m)/(m+5)求实数M的值sin(5л+A)=(m-3)/(m+5).cos(3л-a)=(4-2m)/(m+5)求实数M的值
sin(5л+A)=(m-3)/(m+5).cos(3л-a)=(4-2m)/(m+5)求实数M的值
sin(5л+A)=(m-3)/(m+5).cos(3л-a)=(4-2m)/(m+5)
求实数M的值
sin(5л+A)=(m-3)/(m+5).cos(3л-a)=(4-2m)/(m+5)求实数M的值
sinA=(3-m)/(m+5)
cosA=(2m-4)/(m+5)
m*m-6m+9+4m*m-16m+16=m*m+10m+25
m=8
sin(5л+A)=sin(л+A)=-sinA=(m-3)/(m+5)
sinA=-(m-3)/(m+5)
cos(3л-a)=cos(л-A)=-cosA=(4-2m)/(m+5)
cosA=-(4-2m)/(m+5)
(sinA)^2+(cosA)^2=1
[-(m-3)/(m+5)]^2+[-(4-2m)/(m+5)]^2=1
(m-3)^2...
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sin(5л+A)=sin(л+A)=-sinA=(m-3)/(m+5)
sinA=-(m-3)/(m+5)
cos(3л-a)=cos(л-A)=-cosA=(4-2m)/(m+5)
cosA=-(4-2m)/(m+5)
(sinA)^2+(cosA)^2=1
[-(m-3)/(m+5)]^2+[-(4-2m)/(m+5)]^2=1
(m-3)^2+(4-2m)^2=(m+5)^2
4m^2-32m=0
m=0,m=8
代入检验,因为-1<=cosA<=1,-1<=sinA<=1
显然都符合
所以m=0,m=8
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