(X-1/2y-1)(x-1/2y+1)-(x-1/2y-1)² 运用初二知识化简.
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(X-1/2y-1)(x-1/2y+1)-(x-1/2y-1)²运用初二知识化简.(X-1/2y-1)(x-1/2y+1)-(x-1/2y-1)²运用初二知识化简.(X-1/2y-
(X-1/2y-1)(x-1/2y+1)-(x-1/2y-1)² 运用初二知识化简.
(X-1/2y-1)(x-1/2y+1)-(x-1/2y-1)² 运用初二知识化简.
(X-1/2y-1)(x-1/2y+1)-(x-1/2y-1)² 运用初二知识化简.
(x-y/2-1)(x-y/2+1)-(x-y/2-1)^2
=[(x-y/2)-1][(x-y/2)+1]-[(x-y/2)-1]^2
=(x-y/2)^2-1-(x-y/2)^2+2(x-y/2)-1
=2(x-y/2)-2
=2x-y-2
[(-x-y)(-x+y)-(x+y)^2-x(y-y^2)}÷1/2y
1、y-x/x²-y²2、(x-y)(y-z)(z-x)/(z-y)(y-x)(x-z)
(x-y)(2x-y-1)
(x/x+y-x/y-x-2xy/x.x-y.y)/(1/x-1/y) 分式化简
x²/xy-x/y 3x/4x+y - x-2y/4x+y (1-y/y+x)÷x/y²-x²
2y(x+二分之一y)-[(x+y)(x-y)+2y(y+x)],其中|x-1|=2
（x-y)(x+y)-(x+y)^2+2y(y-x),其中x=1,y=3.
已知x+y=a,2x-y=-2a,求[（x/y-y/x)/(x+y)-x(1/x-1/y)]/[(x+1)/y]的值
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[(-2x-y)^2-(2x+y)(2x-y)]÷2y-1/2y
求(1+y)-2x(1+y)+x(1-y)
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x+2y=2x+y+1=7x-y 求：2x-y?