y=(x^2-2x-1)/(x^2-5x+6)值域
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/23 11:42:41
y=(x^2-2x-1)/(x^2-5x+6)值域y=(x^2-2x-1)/(x^2-5x+6)值域y=(x^2-2x-1)/(x^2-5x+6)值域y(x²-5x+6)=x²-2
y=(x^2-2x-1)/(x^2-5x+6)值域
y=(x^2-2x-1)/(x^2-5x+6)值域
y=(x^2-2x-1)/(x^2-5x+6)值域
y(x²-5x+6)=x²-2x-1
整理
(y-1)x²+(2-5y)x+(6y+1)=0'
x是实数,所以方程有解
判别式大于等于0
所以(2-5y)²-4(y-1)(6y-1)>=0
4-20y+25y²-24y²+28y-4>=0
y²+8y>=0
y(y+8)>=0
y=0
值域(-∞,-8]∪[0,+∞)
x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2
若2x-3y+4=0则x(x*x-1)+x(5-x*x)-6y+7
{6(x-y)-7(x+y)=21 {2(x-y)-5(x+y)=-1
(x-y)/(x+y)=3求( 3x-2y-1)/(x+y-5)
函数,y=3x/(x^2+x+1) ,x
函数y=3x/(x^2+x+1) (x
函数y=2x/x²-x+1(x
{(x+y)/2+(x-y)/3=1,(x+y)-5(x-y)=2.求x=?,y=?
xy²/(x²y-y) × x²/(x²+x)=(x²-3x)/(x²-5x) × 2x-10/(x²-6x+9)=化简求植x²-1/(x²-x-2)除以x/2x-4,其中x=1/2[x-x/(x+1)]除以[x/(2x-4)] ,其中x=√2+1
已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y)
分式的加减:[(x/y-y/x)除以(x+y)+x(1/y-1/x)]除以1+x/y,其中x=5,y=2
化简 3x(x^2-x-1)-(x+1)(3x^-x) X^3(x-y)+x(y-x)
求y=(5x-1)/(4x+2) (x
*-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X ||
因式分解x(x+y)(x-y)-x(x+y)^2
(2x+y-1)(2x-y+1)-(3x+y)(3x-y),其中x=5分之1,
填九宫格帮帮忙.x x 6 x x 7 x x 98 x x x 3 x 1 x x 9 x x 6 x 5 x 3 x x x 3 x x x x 1 8x x x 9 x 1 x x x2 1 x x x x 6 x x x 6 x 7 x 3 x x 1 x x 9 x 2 x x x 47 x x 8 x x 5 x x
已知x+y=a,2x-y=-2a,求[(x/y-y/x)/(x+y)-x(1/x-1/y)]/[(x+1)/y]的值