求y=(5x-1)/(4x+2) (x
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求y=(5x-1)/(4x+2)(x求y=(5x-1)/(4x+2)(x求y=(5x-1)/(4x+2)(x4x+2乘过去整理得.x(4y-5)=-2y-1x=(-2y-1)/(4y-5)因为xy=(
求y=(5x-1)/(4x+2) (x
求y=(5x-1)/(4x+2) (x
求y=(5x-1)/(4x+2) (x
4x+2乘过去
整理得.x(4y-5)=-2y-1
x=(-2y-1)/(4y-5)
因为x
y=(5x-1)/(4x+2)
=(5x+5/2-7/2)/(4x+2)
=5/4-7/(8x+4)
x<0
8x-4<-4
-1/4<1/(8x-4)<0
0<-7/(8x-4)<7/4
5/4<5/4-7/(8x+4)<5/4+7/4=3
所以值域是(5/4,3)
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