x^2-x+y^2+2y+5/4=0 求x^-1+y^0
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x^2-x+y^2+2y+5/4=0求x^-1+y^0x^2-x+y^2+2y+5/4=0求x^-1+y^0x^2-x+y^2+2y+5/4=0求x^-1+y^0(x²-x+1/4)+(y&
x^2-x+y^2+2y+5/4=0 求x^-1+y^0
x^2-x+y^2+2y+5/4=0 求x^-1+y^0
x^2-x+y^2+2y+5/4=0 求x^-1+y^0
(x²-x+1/4)+(y²+2y+1)=0
(x-1/2)²+(y+1)²=0
所以x-1/2=0,y+1=0
x=1/2,y=-1
所以原式=2+1=3
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