y=3^x+3^(-x)(x=/0)的值域
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y=3^x+3^(-x)(x=/0)的值域y=3^x+3^(-x)(x=/0)的值域y=3^x+3^(-x)(x=/0)的值域y=-x^2+2xy=-(x-1)^2+1x=1时y有最大值为1x<
y=3^x+3^(-x)(x=/0)的值域
y=3^x+3^(-x)(x=/0)的值域
y=3^x+3^(-x)(x=/0)的值域
y=-x^2+2x
y=-(x-1)^2+1
x=1时y有最大值为1
x<1时为减函数,所以在0<=x<=1的范围内x=0时,y最小为0
3>=x>1范围内,x=3时候,y最小,为-3
所以y的值域为-3<=y<=1
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