若a^4-10a^2+25+b^4=0,求a,b的值

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若a^4-10a^2+25+b^4=0,求a,b的值若a^4-10a^2+25+b^4=0,求a,b的值若a^4-10a^2+25+b^4=0,求a,b的值a^4-10a^2+25+b^4=0(a^2

若a^4-10a^2+25+b^4=0,求a,b的值
若a^4-10a^2+25+b^4=0,求a,b的值

若a^4-10a^2+25+b^4=0,求a,b的值
a^4-10a^2+25+b^4=0
(a^2-5)^2+b^4=0
平方和四次方大于等于0
相加等于0,若有一个大于0,则另一个小于0,不成立.
所以两个都等于0
所以a^2-5=0,b=0
a^2=5
所以a=±√5,b=0