(2/3)^-1+(π-3)^0+(-2)^-2+丨(-2)^3丨RT
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(2/3)^-1+(π-3)^0+(-2)^-2+丨(-2)^3丨RT(2/3)^-1+(π-3)^0+(-2)^-2+丨(-2)^3丨RT(2/3)^-1+(π-3)^0+(-2)^-2+丨(-2)
(2/3)^-1+(π-3)^0+(-2)^-2+丨(-2)^3丨RT
(2/3)^-1+(π-3)^0+(-2)^-2+丨(-2)^3丨
RT
(2/3)^-1+(π-3)^0+(-2)^-2+丨(-2)^3丨RT
(2/3)^-1+(π-3)^0+(-2)^-2+丨(-2)^3丨
=3/2+1+1/4+8
=10又4分之3
|-2|+(-1)-(π-√3)0次方
|-2|+(π-3)^0-(1/3)^0+(-1)^2010
(π-)^0-(1/2)^-1+(2/3)^2008*(-1.5)^2009
(π-)^0-(1/2)^-1+(2/3)^2008*(-1.5)^2009
计算 (3.14-π)^0-(2分之1)^-2+|-3|
sin(2π/3+λ)=1/2,0
两道计算题1、5^-2-(-4)^-2+(π-1)^0 2、(-1/3)^0+(-1/3)^-1+(-1/3)^-2
(2/3)^-1+(π-3)^0+(-2)^-2+丨(-2)^3丨RT
sin0=0 sin(1/6π)=1/2sin(1/3π)=√3/2sin(1/2π)=1sin(2/3π)=√3/2sin(5/6π)=1/2sin(π)=0sin(-π)=0sin(-5/6π)=-1/2sin(-2/3π)=-√3/2sin(-1/2π)=-1sin(-1/3π)=-√3/2sin(-1/6π)=-1/2sin(7/6π)=-1/2sin(4/3π)=-√3/2sin(5/3π)=-√3/2sin(11/6π)=-1/
50π/3化为2Rπ+a(0(16π+2π)/3 16π + 2π/3?
-1^4+(2008-π)^0+(3)^-1+(1/3)^-2-(-2^3)
1.y=sin(1/2x+π/6),x属于[0,π/3] 2.y=-cos(3x-π/3),x属于[-π/3,π/3]
y=2cos(2x+π/3)+1,x∈【0,π/2】的值域
-2²-1/根号2+|(-2)²-1|+(π-3)^0+根号2/2
-2²-1/根号2+|(-2)²-1|+(π-3)^0+根号2/2
已知a属于(0,π),cos(π/3+a)=1/3,求sin(π/3-2a),
sin(a+π/2)=1/3,a属于(-π/2,0),则tan a=
函数y=2tan(1/2x+π/3)的图像的一个对称中心是( )A (π/6,0) B (2π/3,-3√3) C(-2π/3,0) D(0,0)