triangleABC has the following dimensions:AC=10,AB=8,and angleACB=20degreesa) Calculate the 2 possible values for angleCABb)sketch and label the 2 possible shapes for triangleABCI want process and picture!thank u
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triangleABC has the following dimensions:AC=10,AB=8,and angleACB=20degreesa) Calculate the 2 possible values for angleCABb)sketch and label the 2 possible shapes for triangleABCI want process and picture!thank u
triangleABC has the following dimensions:
AC=10,AB=8,and angleACB=20degrees
a) Calculate the 2 possible values for angleCAB
b)sketch and label the 2 possible shapes for triangleABC
I want process and picture!
thank u
triangleABC has the following dimensions:AC=10,AB=8,and angleACB=20degreesa) Calculate the 2 possible values for angleCABb)sketch and label the 2 possible shapes for triangleABCI want process and picture!thank u
可以把过程告诉你,以C点为圆心,CA=10为半径作圆C,在圆C上任取一点A0,作角A0CD=20degrees,再以A0为圆心,A0C=8画圆,与射线CD交B1,B2两点,即为所求.
中文能否看懂,若看不懂,再翻译成英文
2.
y=cos(2x-π/3)+2sin(x-π/4)sin(x+π/4)
=cos(2x-π/3)+2[-1/2*[cos2x-cos(π/2)]
=cos(2x-π/3)-cos2x
=2sin(2x-π/6)sin(π/6)
=2sin(2x-π/6)
(1)最小正周期为π，图像的对称轴方程为π/12+ -（π/4）*k（k是整数...
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2.
y=cos(2x-π/3)+2sin(x-π/4)sin(x+π/4)
=cos(2x-π/3)+2[-1/2*[cos2x-cos(π/2)]
=cos(2x-π/3)-cos2x
=2sin(2x-π/6)sin(π/6)
=2sin(2x-π/6)
(1)最小正周期为π，图像的对称轴方程为π/12+ -（π/4）*k（k是整数）
(2)在区间[-π/12,]上的值域：
π/12-π/4=-π/6,π/6<-π/12π<π/12;
π/12+ π/4<π/2<π/12+ (π/4)*2
值域为[y([-π/12),2],即[-√3,2]
3.f（x）=√3sin(ωx+φ)-cos(ωx+φ)(0＜φ＜π，ω＞0)
=-2（1/2*cos(ωx+φ)-√3/2*sin(ωx+φ)）
=-2cos(ωx+φ+π/3)
f（x）为偶函数,且0＜φ＜π，则φ+π/3=π，φ=2π/3；
图像的两相邻对称轴间的距离为π/2，则周期T=π,则ω=2；
f（x）=2cos(2x).
剩下的自己做。。。
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