求sin(-1320)cos1110+cos(-1020)sin750的值
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求sin(-1320)cos1110+cos(-1020)sin750的值求sin(-1320)cos1110+cos(-1020)sin750的值求sin(-1320)cos1110+cos(-10
求sin(-1320)cos1110+cos(-1020)sin750的值
求sin(-1320)cos1110+cos(-1020)sin750的值
求sin(-1320)cos1110+cos(-1020)sin750的值
1
sin(-1320)cos1110+cos(-1020)sin750
=sin(1440-1320)cos(960+150)+cos(-960-60)sin(720+30)
=sin120°cos150°+cos60°sin30°
=√3/2*(-√3)/2+1/4
=-3/4+1/4
=-1/2
sin(-1320)cos1110+cos(-1020)sin750=sin120cos30+cos60sin30=3/4+1/4=1
求sin(-1320)cos1110+cos(-1020)sin750的值
sin(-1320°)cos1110°的值
sin(-1380`)cos1110`+ cos(-1020`)sin750`+tan495`求过程
sin(-1320)cos1110+cos(-1020)sin750+tan495的值.
sin(-1320°)、cos1110°、cos(-1020°)、sin750°、tan495°等于多少
求值 sin(-1320°)cos1110°+cos(-1020°)sin750°+cos495°
sin-1320度cos1110度+cos-1020度sin750度+tan495度=?
sin(-1320°)cos1110°+cos(-1020°)sin750°+tan495°
sin(-1395)cos1110+cos(-1020)sin750
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