x=2t^2 +1 y= sint 求dy/dx是多少?x 等于2t的平方再加1,

求x=e^t*cost,y=e^t*sint所确定的函数的二阶导数,求讲解x't=(e^t)(sint+cost)y't=(e^t)(cost-sint)x''t=(e^t)(sint+cost+cost-sint)=2(e^t)costy''t=(e^t)(cost-sint-sint+cost)=-(e^t)sintdy/dx=(cost-sint)/(sint+cost)d^2 y/d(x^2)=d(dy/dx)/dx=(y''x x=(e^t)sint y=(e^t)cost 求d^2y/dx^2 设x=1+t^2、y=cost 求 dy/dx 和d^2y/dx^2 sint-tcost/4t^3 和 sint-tcost/4t^2 哪个对?设x=1+t^2、y=cost 求 dy/dx 和d^2y/dx^2sint-tcost/4t^3 和 sint-tcost/4t^2 哪个对? 求微分的题目一道,x=e^(-t)sint,y=e^tcost,求 d^2y/dx^2 设x=t^2+cost,y=1-sint,求dy/dx x=a(t-sint),y=a(1-cost),求y^2对x,y的二重积分 参数方程：x=5(t-sint) y=5(1-cost) 求d^2y/dx^2 dy/dx我会求 设X=a(t-sint) Y=a(1-cost) ,求d^2y/dx^2答案是-1／a(1-cost)^2 求导数 x=3t²+2t+3 y=e^y*sint+t 求 dy/dx 此参数方程怎么解?x=2(t-cost)y=2(1-sint)求dy/dx.为什么是这样解呢?dx= 2(1+sint)dtdy= -2costdy/dx = -cost/(1+sint) 此参数方程为什么这么解x=2(t-cost)y=2(1-sint)求dy/dx.答案是dy/dx = -cost/(1+sint)为什么dx= 2(1+sint)dt为什么dy= -2cost 求∫∫y^2dσ,其中D是由摆线x=a(t-sint),y=a(1-cost)(0≤t≤2π)的一拱与x轴所围成 高数:摆线x=a(t-sint),y=a(1-cost)(0《=t《2π)确定隐函数y=y(x),求dy/dx 证明：f(x)=x*cos(x)不是周期函数证明：假设y=xcosx是周期函数,因为周期函数有f(x+T)=f(x)xcosx=（x+T)cos(x+T)=xcosx*cosT-xsinx*sinT+Tcosx*cosT-Tsinx*sinT所以cosT=1 T=kπ/2-xsinx*sinT+Tcosx*cosT-Tsinx*sinT=0-xsinx*sinT-Tsinx*si x=3t²+2t+3 y=(e的y次幂)·sint + 1 ,求在t=0时 dy/dx=? x=3t²+2t+3 y=(e的y次幂)·sint + 1 ,求在t=0时 dy/dx=? sint t=x的三次方 求sint导数? 高数!设z=e^(x-2y),而x=sint,y=t^3,求dz/dt