1/2*3+31/3*5...1/9*11
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1/2*3+31/3*5...1/9*111/2*3+31/3*5...1/9*111/2*3+31/3*5...1/9*11为你提供精确解答应该为:1/2*3+1/3*5...1/9*11=(1/2
1/2*3+31/3*5...1/9*11
1/2*3+31/3*5...1/9*11
1/2*3+31/3*5...1/9*11
为你提供精确解答
应该为:
1/2*3+1/3*5...1/9*11
=(1/2-1/3)+(1/2)【(1/3-1/5)+(1/5-1/7)+(1/7-1/9)+(1/9-1/11)】
=1/6+(1/2)(1/3-1/5+1/5-1/7+1/7-1/9+1/9-1/11)
=1/6+(1/2)(1/3-1/11)
=1/6+8/33
=35/66
1/(1×3)+1/(3×5)+……+1/(9×11)
=1/2(1-1/3)+1/2(1/3-1/5)+……+1/2(1/9-1/11)
=1/2[(1-1/3)+(1/3-1/5)+……+(1/9-1/11)]
=1/2(1-1/3+1/3-1/5+……+1/9-1/11)
=1/2(1-1/11)
=1/2×10/11
=5/11
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1/(1×3)+1/(3×5)+……+1/(9×11)
=1/2(1-1/3)+1/2(1/3-1/5)+……+1/2(1/9-1/11)
=1/2[(1-1/3)+(1/3-1/5)+……+(1/9-1/11)]
=1/2(1-1/3+1/3-1/5+……+1/9-1/11)
=1/2(1-1/11)
=1/2×10/11
=5/11
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1/2*3+31/3*5...1/9*11
1,2,3,3,7,5,15,9,31,( )
(31+1/3)*(41+1/2)-(11+1/3)*(41+1/2)*2-(9+1/2)*(11+1/3)
31 1/3*41 1/2 -11 1/3*41 1/2*2-9 1/2*11 1/3
1,2,3,4,5.
1,2,3,4,5.
1,2,3,4,5.
7/9:( )=1/2:3/5.括号里填几?
[(1+29)*(1+29/2)*...*(1+29/30)*(1+29/31)]/[(1+31)*(1+31/2)*(1+31/3)*...*(1+31/28)*(1+31/29)=?[(1+29)*(1+29/2)*...*(1+29/30)*(1+29/31)]/[(1+31)*(1+31/2)*(1+31/3)*...*(1+31/28)*(1+31/29)〕=?上面那道题少了一个中括号
-1,3,5.,9 .24点急用
1/2+1/3+1/4+1/5.+1/100,
一、1/11-1/31+2/11-12/31+3/11-13/31+……+10/11-20/31二、1/(5*7)+1/(7*9)+1/(9*11)+1/(11*13)
根据数字猜成语:3 3 3 2 2;1 3 5 7 9;1 2 3 4 5.
1*3+3*5+5*7+7*9+,+29*31
x-2*3+1=31
1/1*2*3+1/2*3*4+1/3*4*5.+1/9*10*11= 1/1*2*3+1/2*3*4+1/3*4*5.+1/9*10*11=1+(1/1+2)+(1/1+2+3)......+(1/1+2+3+....+100) =
5,计算行列式1 1 2 31 2 3 -13 -1 -1 -22 3 -1 -1
1-3+2-6+3-9+4-12+.+31-93+32-96+33-99