vfp程序错误求指出X=THIS.VALUETHISFORM.GRDDMB.RECORDSOURCETYPE=4DO CASECASE X=1THISFORM.GRDDMB.RECORDSOURCE="SELECT * FROM DMB WHERE LX="政治面貌""CASE X=2THISFORM.GRDDMB.RECORDSOURCE="SELECT * FROM DMB WHERE LX="文化程度""CASE X=3THISF

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vfp程序错误求指出X=THIS.VALUETHISFORM.GRDDMB.RECORDSOURCETYPE=4DOCASECASEX=1THISFORM.GRDDMB.RECORDSOURCE="S

vfp程序错误求指出X=THIS.VALUETHISFORM.GRDDMB.RECORDSOURCETYPE=4DO CASECASE X=1THISFORM.GRDDMB.RECORDSOURCE="SELECT * FROM DMB WHERE LX="政治面貌""CASE X=2THISFORM.GRDDMB.RECORDSOURCE="SELECT * FROM DMB WHERE LX="文化程度""CASE X=3THISF
vfp程序错误求指出
X=THIS.VALUE
THISFORM.GRDDMB.RECORDSOURCETYPE=4
DO CASE
CASE X=1
THISFORM.GRDDMB.RECORDSOURCE="SELECT * FROM DMB WHERE LX="政治面貌""
CASE X=2
THISFORM.GRDDMB.RECORDSOURCE="SELECT * FROM DMB WHERE LX="文化程度""
CASE X=3
THISFORM.GRDDMB.RECORDSOURCE="SELECT * FROM DMB WHERE LX="民族""
ENDCASE
THISFORM.REFRESH
THISFORM.GRDDMB.RECORDSOURCE="SELECT * FROM DMB WHERE LX="政治面貌""
这句哪里错了

vfp程序错误求指出X=THIS.VALUETHISFORM.GRDDMB.RECORDSOURCETYPE=4DO CASECASE X=1THISFORM.GRDDMB.RECORDSOURCE="SELECT * FROM DMB WHERE LX="政治面貌""CASE X=2THISFORM.GRDDMB.RECORDSOURCE="SELECT * FROM DMB WHERE LX="文化程度""CASE X=3THISF
引号多了
THISFORM.GRDDMB.RECORDSOURCE="SELECT * FROM DMB WHERE LX=政治面貌"

vfp程序错误求指出X=THIS.VALUETHISFORM.GRDDMB.RECORDSOURCETYPE=4DO CASECASE X=1THISFORM.GRDDMB.RECORDSOURCE=SELECT * FROM DMB WHERE LX=政治面貌CASE X=2THISFORM.GRDDMB.RECORDSOURCE=SELECT * FROM DMB WHERE LX=文化程度CASE X=3THISF vfp中 x=val(thisform.text1.value)和x=thisform.text1.value 的区别 a=val(thisform.text1.value)在vfp中是什么意思 vfp编写程序求:X +X^2+X^3+X^4+.x^N的值 有如下类定义 class Sample{ public:Sample(int x):ref(x){} //1 private:Sample():ref(0){} //2staric int val=5;//3const int ref;};//4请问 上述程序,错误的语句是————? 求高手解答vfp程序改错题! 指出下面程序重点错误,在错误处说明出错原因#includeclass A{private:int a;public:void setA(int x){a=x;}void ShowA() const {cout 怎样用matlab解下面积分方程!大谢!已知Q(x)为0.1,0.01,0.001,求x用matlab试了半天,还是不对...Q=0.1;f=@(x)exp(-x.*x/2);b=inf;%上限val=Q*sqrt(2*pi);g=@(a)quadl(f,a,b)-val;a=fsolve(g,b)上面程序不对... VFP X=X+Y Y=Y+2程序里有这个语句 X=X+Y Y=Y+2在VFP语言里怎么解释? 输入n,求s=1!+2!+...+n!的前n项和.是VFP程序 求下面程序的错误和如何修改matlab的>> a=0;while(1.1-a)>1c=[-0.05 -0.27 -0.19 -0.185 -0.185];Aeq=[1 1.01 1.02 1.045 1.065]; beq=[1];A=[0 0.025 0 0 0;0 0 0.015 0 0;0 0 0 0.055 0;0 0 0 0 0.026];b=[a;a;a;a];vlb=[0,0,0,0,0];vub=[];[x,val]=lin 求下面matlab程序的错误和修改结果>> a=0;while(1.1-a)>1c=[-0.05 -0.27 -0.19 -0.185 -0.185];Aeq=[1 1.01 1.02 1.045 1.065]; beq=[1];A=[0 0.025 0 0 0;0 0 0.015 0 0;0 0 0 0.055 0;0 0 0 0 0.026];b=[a;a;a;a];vlb=[0,0,0,0,0];vub=[];[x,val]=linpro 下列表达式不符合VFP规则的是A 04/07/2001B T+TC VAL(1234)D 2X>15 vfp程序题一道 vfp程序问题 vfp程序疑问 C语言中 val 有这么一个C语言程序 :int i;long val;for(i=0;i ajaxtest.php?u='+$(this).val()这句话什么意思