已知数列an满足a1=1,an=1+2a(n/2)n为偶数,1/2+2a(n-1/2)n为奇数,n=2,3,4.设bn=a2(n-1)+1,n=1,2,3,4.则bn
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已知数列an满足a1=1,an=1+2a(n/2)n为偶数,1/2+2a(n-1/2)n为奇数,n=2,3,4.设bn=a2(n-1)+1,n=1,2,3,4.则bn已知数列an满足a1=1,an=1
已知数列an满足a1=1,an=1+2a(n/2)n为偶数,1/2+2a(n-1/2)n为奇数,n=2,3,4.设bn=a2(n-1)+1,n=1,2,3,4.则bn
已知数列an满足a1=1,an=1+2a(n/2)n为偶数,1/2+2a(n-1/2)n为奇数,n
=2,3,4.设bn=a2(n-1)+1,n=1,2,3,4.则bn
已知数列an满足a1=1,an=1+2a(n/2)n为偶数,1/2+2a(n-1/2)n为奇数,n=2,3,4.设bn=a2(n-1)+1,n=1,2,3,4.则bn
过程如图
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