求 1/2+1/(2*3)+1/(3*4)+1/(4*5)+……+1/(2008*2009)的值
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求1/2+1/(2*3)+1/(3*4)+1/(4*5)+……+1/(2008*2009)的值求1/2+1/(2*3)+1/(3*4)+1/(4*5)+……+1/(2008*2009)的值求1/2+1
求 1/2+1/(2*3)+1/(3*4)+1/(4*5)+……+1/(2008*2009)的值
求 1/2+1/(2*3)+1/(3*4)+1/(4*5)+……+1/(2008*2009)的值
求 1/2+1/(2*3)+1/(3*4)+1/(4*5)+……+1/(2008*2009)的值
1/2+1/(2*3)+1/(3*4)+1/(4*5)+……+1/(2008*2009)
＝1－1/2＋1/2－1/3＋1/3-1/4+1/5－……＋1/2008-1/2009
＝1-1/2009
＝2008/2009
希望杯的题来吧?
用裂项公式做。1/(n*(n+1)=1/n-1/(n+1).代入后经过抵消就只剩个1/2009啦