求解main(){unsigned a=32768;int b;b=a;printf("b=%d\n",b);}

来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/25 02:46:44
求解main(){unsigneda=32768;intb;b=a;printf("b=%d\n",b);}求解main(){unsigneda=32768;intb;b=a;printf("b=%d

求解main(){unsigned a=32768;int b;b=a;printf("b=%d\n",b);}
求解main(){unsigned a=32768;int b;b=a;printf("b=%d\n",b);}

求解main(){unsigned a=32768;int b;b=a;printf("b=%d\n",b);}
main()
{unsigned a=32768; //unsigned存储的数据范围是0~65535
int b;
b=a;
printf("b=%d\n",b); //所以结果是 32768
}

求解main(){unsigned a=32768;int b;b=a;printf(b=%d ,b);} main( ) {unsigned int a=3,b=10; printf(%d/n,a1); } 新手求解这个程序的意思,#include #define uint unsigned int#define uchar unsigned char uchar a,b,temp,table[]={0xe7,0xdb,0xbd,0x7e,0xbd,0xdb,0xe7}; void delay(uint z){ uint x,y; for(x=z;x>0;x--)for(y=110;y>0;y--); }void main(){ while(1) { te #include void main() { unsigned char a,b; a=4|3; b=4&3; printf(%d,%d,a,b); } 求补码怎么求的...#include #include void main (){unsigned short int a;unsigned short int getbits(unsigned short);printf ( input an octal number:);scanf (%o,&a);printf (%o ,getbits(a));}unsigned short int getbits (unsigned short value){u #include main() {unsigned int a=65535; printf(a=%d ,a); } 运算结果 a=-1#includemain(){unsigned int a=65535;printf(a=%d ,a);}运算结果a=-1为什么是等于-1呢? main() { unsigned char a,b; a=4|3; b=4&3; printf(%d %d ,a,b); }执行后输出结果 #include sbit p1_1=P1^0; unsigned int a ; void main() {while(1) { a=51000; p1_1=0; while(#includesbit p1_1=P1^0;unsigned int a ;void main(){while(1) { a=51000; p1_1=0; while(a--);a=51000;while(a--);p1_1=1; a=51000; while(a--);a=51000; while(a--); }}s 关于位域运算 麻烦帮解释下下列程序#includevoid main(){struct bs{unsigned a:1;unsigned b:3;unsigned c:4;} bit,*pbit;bit.a=1;bit.b=7;bit.c=15;printf(%d,%d,%d ,bit.a,bit.b,bit.c);pbit=&bit;pbit->a=0; //此后三行是什么意思pbit-> 谁能告诉我以下程序结果,unsigned fun6(unsigned num){unsigned k=1;do{k*=num%10;num/10;}while(num);return(k);}main(){unsigned n=26;printf(%d ,fun6(n));}是c语言题 #include sbit a=P1^0; sbit b=P3^2; unsigned int n; void main(void) { while(1) {if(b=0)a=#include sbit a=P1^0;sbit b=P3^2;unsigned int n;void main(void){while(1){if(b=0)a=0;for(n=0;n unsigned char ctoa(char a[]){unsigned char c=0;for(int i=0;i 一道C语言题目~求教!#include #include int main(){unsigned x = 10;getbits(x,4,3);return 0;}unsigned getbits(unsigned x,int p,int n){return (x >> (p+1-n) & 0 unsigned int gcd(unsigned int a,unsigned int b){while(b^=a^=b^=a%=b);return a;} #include main() { unsigned char a=8,c; c=a>>3; printf(%d ,c); } 程序这里的a是字符型变量,赋给它8,为什么是整形十进制的8,而不是ACSII码呢? 有以下程序 main( ) { unsigned char a,b; a=4|3; b=4&3; printf(“%d %d ”,a,bvc答案错误 我想问下他是咋运行的 #include stdio.hvoid main(void){ int a=10; int *p = &a; unsigned int b = (unsigned int)p; printf(0x%x ,p); printf(0x%x ,b); int *out = (int *)b; printf(0x%x , *out);} 很奇怪,只能打印前两个printf,最后一个 关于一道程序填空题的疑惑#include #include #include unsigned long fun(char *s){unsigned long t = 0;int k;int i = 0;i = strlen(s);for (--i; i>=0; i--){k = s[i]-'0';t = t*10+k;}return t;}main(){char str[8];printf(Enter a string made up of '