化简cos(π/4+x)-sin(π/4+x)/cos(π/4 +x)+sin(π/4 +x)的值是 答案是-tanx 要详细过程.要这道题的详细过程.

化简sin(x-π/4)+cos(x+π/4) cos(x+π/4)+sin(x+π/4)化简 化简1+sin x/cos x·sin2x/2cos²（π/4-x/2） 化简sin(3π-x)cos(x-3/2)cos(4π-x)/tan(x-5π)cos(π/2+x)sin(x-5/2π) 化简sin(3π-x)cos(x-3/2)cos(4π-x)/tan(x-5π)cos(π/2+x)sin(x-5/2π) 化简2sin^2[(π/4)+x]+根号3（sin^x-cos^x）-1 化简sin(x+7π/4)+cos(x-3π/4）步骤我已经找到撒sin(x+7π/4)+cos(x-3π/4)=sin(x+2π-π/4)+cos(x-π+π/4)我问下这一步是在干嘛?=sin(x-π/4)+cos[-(π-x-π/4)]=sin(x-π/4)+cos(π-x-π/4)=sin(x-π/4)-cos(x+π/4)=sin(x-π/4)-cos(x+π/2- 化简sin^4x-sin^2x+cos^2x 化简:sin^4 x-sin^2 x+cos^2 x 化简cos^4x+sin^4x 化简:cos^4(X)-sin^4(X) 化简sin^4x+cos^2x 化简(sin^2x-cos^4x+cos^2x-sin^4x)/(sin^2x-cos^6x+cos^2x-sin^6x) sin（π/4-x)为什么等于cos(x+π/4) 函数y=sin(x)cos(x+ π/4)+cos(x)sin(x+π/4)的最小正周期是 [（sin x-cos x）/(sin x+cos x)]^4 求定积分 积分区间0-π/4 f(x)=cos(2x-x/3)+2sin(x-π/4)sin(x+π/4)sin(x+π/4)化简. （1）化简:根号2sin(π/4-x)+根号6cos(π/4-x)（2）sin(67°-x)cos(x-22°)+cos(67°-x)cos(112°-x)的值为