log(2x-3)(x^2-2x-2)>0,(2X-3)是底数
来源:学生作业帮助网 编辑:六六作业网 时间:2024/08/29 06:59:08
log(2x-3)(x^2-2x-2)>0,(2X-3)是底数log(2x-3)(x^2-2x-2)>0,(2X-3)是底数log(2x-3)(x^2-2x-2)>0,(2X-3)是底数你可以设2x-
log(2x-3)(x^2-2x-2)>0,(2X-3)是底数
log(2x-3)(x^2-2x-2)>0,(2X-3)是底数
log(2x-3)(x^2-2x-2)>0,(2X-3)是底数
你可以设2x-3=t 再讨论一下 或者把log(2x-3)(x^2-2x-2)看成ln(x^2-2x-2)/ln(2x-3)
log(0.5x)(2)-log(0.5x^3)(x^2)=log(0.5x^3)(4)
log(2)(x+4)=3^x
log(2)(x)log(2)(4x)-3log(2)(x)-12=0
(log(2)(x))^3-4(log(4)(x))^2+log(16)(x)=0
log(x+5)=log(x)+log(2) log(8)+log(x)=log(24) 2log(x)=log(2x)+log(3)
[( log(x^2) + log(x^4) )/ log(100 x)] = 4 求X
2log(m)y-log(m)x-log(m)z
2 log(3x)= log 4 +log(6-x)怎么求...急
已知log(2){log(3)[log(4)(x)]}=5^0,则x=?
1/log(2)x+1/log(3)x+1/log(4)x=1,x=?
log(2x)+log(3y)-log(2z) 怎么化简?log3(x^2-2x-6)=2 log(3x+6)=1+log(x)求解,求每步详...log(2x)+log(3y)-log(2z) 怎么化简?log3(x^2-2x-6)=2 log(3x+6)=1+log(x)求解,
solve:log(x)+log(2x)=2
log(X+5)+log(X+2)=1
log₂X 怎样变为log₂(2X)
试解关于x的不等式log(2)x+4log(3)x+12log(8)x+n·2^(n-1)·log(2^n)x
log底2(x-2)
log根号2(X-1)
x=log a 2