int a[3][8],*p; printf("\n a+0=%-10p",a+0);

void fun(int *a,int *b) { int *c; c=a;a=b;b=c; } main() { int x=3,y=5,*p=&x,*q=&y; fun(p,q);...void fun(int *a,int *b){ int *c; c=a;a=b;b=c;}main(){ int x=3,y=5,*p=&x,*q=&y; fun(p,q); printf(%d,%d,,*p,*q); fun(&x,&y); prin%d,%d ,*p,*q);}两 void fun(int *a,int *b) { int *c; c=a;a=b;b=c; } main() { int x=3,y=5,*p=&x,*q=&y; fun(p,q);...void fun(int *a,int *b){int *c;c=a;a=b;b=c;}main(){int x=3,y=5,*p=&x,*q=&y;fun(p,q); printf(%d,%d,,*p,*q);fun(&x,&y); prin%d,%d ,*p,*q);}两次调用 int a[3][3]={{1,2,3},{4,5,6},{7,8,9}}; int **p; p=(int**)a; 其中p=(int**)a;是什么意思啊 int a[3][8],*p; printf( a+0=%-10p,a+0); 若有定义int a[8],*p=a;,则*(p+3)表示_____ main(){int a[ ]={ 2,5,3,6,8}; int *p,i=1,s=0; for ( p=a; p 不知道下面的这个程序是怎么计算的,public class abc{public static void main(String args[]){ int i,s = 0 ;int a[ ] = { 10 ,20 ,30 ,40 ,50 ,60 ,70 ,80 ,90 };for ( i = 0 ; i < a.length ; i ++ )if ( a[i]%3 = = 0 ) s += a[i] ;System.out.prin int[][4]={1,2,3,4,5,6,7,8};int(*p)[4]=a;则表达式**（p+1）-*(*p+1)的值是? int a[]={1,2,3,4,5,6,7,8,9},*p; for(p=a,p #include void main(){ int b=3;int a; int arr[]={6,7,8,9,10}; int *ptr=arr; *(ptr++)+=123;#include using namespace std;void main(){ int b=3;int a; int arr[]={6,7,8,9,10}; int *ptr=arr; *(ptr++)+=123; printf(%d,%d ,*(p public cIass Test {public static void main(String args[]) {int a = 1,b = 2;int c = a + b++;System.ou t.prin tln( c++);System.out.println(c + a);}} 8,执行以下程序段后,m的值为（）int a[2] [3]={{1,2,3},{4,5,6};int m,*p;p=&a[0][0];m=(*p)*(*(p+2))*(*(p+4)); #include void main( ) { int a=3,b=5; int *p,*q; void f1(int x,int y);void f2(int *x,int *y);p=&a; q=&b;f1(*p,*q) ;printf(a=%d ,b=%d ,a,b);f2(p,q);printf(a=%d ,b=%d ,a,b);}void f1(int x,int y) { int t;t=x; x=y; y=t;}void f2(int *x,int *y) { int 哪位高手帮忙看下二分法解方程哪里出错了#include #include #include #include int n; double c[16]; double Func(double); int BisectRoot(double,double,double,double,double *,int,int *); int main() { int i,m; double a,b,h,eps,*x; prin struct st{int x,int*y;}*p; int s[]={5,6,7,8} st a[]={10,&s[0],20,&s[1]30,&[2],40,&s[3]} main( ) {p=a;cout int *p,a=3；*p=&a;&p表示什么? int a[ ][3]={1,2,3,4,5,6,7,8,9,10,11,12}；int*p=a；求 *(*(a+2)+2)的含义(或值 c语言的问题 int a[3][4] = {1,2,3,4,5,6,7,8,9,10,11,12}; int (*p)[4]; p = a;以上为定义,为啥不能使p[0] = p[1];