(x-5y)(-x-5y)-(-x+5y)^2,其中x=二分之一,y=-1帮帮我解决
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(x-5y)(-x-5y)-(-x+5y)^2,其中x=二分之一,y=-1帮帮我解决(x-5y)(-x-5y)-(-x+5y)^2,其中x=二分之一,y=-1帮帮我解决(x-5y)(-x-5y)-(-
(x-5y)(-x-5y)-(-x+5y)^2,其中x=二分之一,y=-1帮帮我解决
(x-5y)(-x-5y)-(-x+5y)^2,其中x=二分之一,y=-1
帮帮我解决
(x-5y)(-x-5y)-(-x+5y)^2,其中x=二分之一,y=-1帮帮我解决
(x-5y)(-x-5y)-(-x+5y)^2
=(-5y+x)(-5y-x)-x^2-25y^2+10xy
=25y^2-x^2-x^2-25y^2+10xy
=-2x^2+10xy
把x=1/2 y=-1代入
-2x^2+10xy =-2/11
解析：(-5y+x)(-5y-x) 平方差公式.
（a+b）乘（a-b）=a^2-b^2
(-x+5y)^2 完全平方
（x+y-5)*（x+y-5)+（x-y+3)=0 x*x-y*y
已知:3x-5y=0,求x/y,x-y/y,x-y/x
计算：5x/x-y+ 5y/y-x
5x/x-y+5y/y-x
(5)a(x+y)-b(x+y)-x-y因式分解
5x(x-y)+2y(x-y)
化简:5(x-y)+2(x+y)-3(x-y)
x+y=5; x^y+y^x=17
(y-x)(x-y)^3(y-x)^5怎么算
x-y+5y-4y
已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y)
若(X×X+Y×Y)(X×X+Y×Y-5)=36,则X×X+Y×Y＝
4x+2y-5x-y
(x+5y)(x-7y-1)
-X²y+ 5X²y
(2x-3y)-(5x-y)
(2X-3y)-(5x-y)
y/5x² * (-x/y)