lingo中的语法问题程序如下sets:r/1..2/:a;e/1..4/:b;link(r,e):c,x;endsetsmin=@sum(link(i,j):c(i,j)*x(i,j));ST@for(r(i): @sum(e(j):x(i,j))=a(i));@for(e(j): @sum(r(i):x(i,j))=b(j));end错误如截图:

来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/20 17:13:44
lingo中的语法问题程序如下sets:r/1..2/:a;e/1..4/:b;link(r,e):c,x;endsetsmin=@sum(link(i,j):c(i,j)*x(i,j));ST@fo

lingo中的语法问题程序如下sets:r/1..2/:a;e/1..4/:b;link(r,e):c,x;endsetsmin=@sum(link(i,j):c(i,j)*x(i,j));ST@for(r(i): @sum(e(j):x(i,j))=a(i));@for(e(j): @sum(r(i):x(i,j))=b(j));end错误如截图:
lingo中的语法问题
程序如下
sets:
r/1..2/:a;
e/1..4/:b;
link(r,e):c,x;
endsets
min=@sum(link(i,j):c(i,j)*x(i,j));
ST
@for(r(i):  @sum(e(j):x(i,j))=a(i));
@for(e(j):  @sum(r(i):x(i,j))=b(j));
end
错误如截图:

lingo中的语法问题程序如下sets:r/1..2/:a;e/1..4/:b;link(r,e):c,x;endsetsmin=@sum(link(i,j):c(i,j)*x(i,j));ST@for(r(i): @sum(e(j):x(i,j))=a(i));@for(e(j): @sum(r(i):x(i,j))=b(j));end错误如截图:
sets:
r/1..2/:a;
e/1..4/:b;
link(r,e):c,x;
endsets
min=@sum(link(i,j):c(i,j)*x(i,j));
ST !这个是什么?lingo语法里没有这个;
@for(r(i):@sum(e(j):x(i,j))=a(i));
@for(e(j):@sum(r(i):x(i,j))=b(j));
end

lingo中的语法问题程序如下sets:r/1..2/:a;e/1..4/:b;link(r,e):c,x;endsetsmin=@sum(link(i,j):c(i,j)*x(i,j));ST@for(r(i): @sum(e(j):x(i,j))=a(i));@for(e(j): @sum(r(i):x(i,j))=b(j));end错误如截图: 关于LINGO程序lingo程序如下:sets:a/1..5/:x; endsets data:x=1,2,3,4,5;enddata 若知道a(i):x(i)=5,如何写出程序求出i的值 我在使用lingo时出现THE MODEL DIMENSIONS EXCEED THE CAPACITY OF THIS VERSION.哪位大虾可以告诉我是什么地方出了问题.如何解决,程序应该不用出错.谢谢.程序如下:model:title CUMCM-2003B-01;sets:cai / 1..10 /:crate, lingo中sets是什么? 程序中的语法是什么意思 lingo求不出可行解程序对应的方程组如上所示,lingo程序如下:model: sets: plan/1..36/;分配方法(堆数)有36种; raw/1..14/:l,total;第二档原料有14种,l是原料长度,total是各个原料的根数; require Lingo求不出可行解程序对应的方程组如上所示,lingo程序如下:model: sets: plan/1..36/;分配方法(堆数)有36种; raw/1..14/:l,total;第二档原料有14种,l是原料长度,total是各个原料的根数; require 这个lingo程序错在哪?我编了个lingo程序,测试的时候出错,感激不尽~以下是程序“MODEL:title 码流提取问题;SETS:job/1..5/;worker/1..16/;assign(job,worker):x,a,b;ENDSETSDATA:a=30.8667,32.7657,35.4304,37.781,40.3113,28.6755, lingo程序:model:sets:product/1..3/:a,b; row/1..5/:c,d,y; num/1..9/:x; endsets其中的product和num该怎么用?还有平时不是用的col么而不是num区别在哪? lingo问题 错误代码29代码如下:model: !需求分配;sets: !定义集合;plant/p1..p8/: capacity; market/m1..m8/: demand; links(plant, market): cost, volume;endsetsmin=@sum(links: cost*volume); !目标函数;@for(market(J): @sum(plant( lingo 集中“ 为什么这样表示?原程序如下:•model:•!6发点8收点运输问题; •sets:• warehouses/wh1..wh6/:capacity; • vendors/v1..v8/:demand; • links(warehouses,vendors):cost,volume; •endsets 这个lingo程序问题到底出在哪里,是不是这个数学问题无法用LINGO求解呢?model:sets:p/1..20/:x,y,t,m,a,b,c;!定义集及其属性;endsetsinit:x=400,400,400,400,400,400,400,400,400,400,400,400,400,400,400,400,400,400,400,400;!初 lingo程序在如下程序中:MODEL:Traveling Salesman Problem for the cities ofAtlanta,Chicago,Cincinnati,Houston,LA ;SETS:CITY / 1..5/:U; U( I) = sequence no.of city;LINK( CITY,CITY):DIST,The distance matrix;X; X( I,J) = 1 if we use link I,J;ENDS 帮我运行个lingo的程序,我这边运行不了程序如下:model:sets:cities/1..6/:u; link(cities,cities):dist,x;endsetsn=@size(cities);data:dist=0 5600 3500 2100 5100 60005600 0 2100 5700 7800 70003500 2100 0 3600 6800 68002100 5700 3600 0 51 Lingo 那里出错了啊?model:title 物流仓库选址问题lingo求解程序;sets:store/1..12/:w,s,m;sale/1..12/:d;links(store,sale):C,p,x;endsetsdata:从仓库i向销售中心j运送货物的运送总成本;C=100,80,50,50,60,100,120,90,60,100,120, lingo的运行错误问题我的lingo程序模型是这样:MODEL:SETS:QUARTERS/1..1000/:X;ENDSETSMIN = @SUM(QUARTERS(i)|@MOD(i,2)#EQ#0:X(i);) - @SUM(QUARTERS(i)|0#NE#@MOD(i,2):X(i););@for(QUARTERS(i):@sum(QUARTERS(i):X(i)) >= 1000 ;);@for(QUARTERS( lingo错误代码11.貌似是定义集的语法问题. 英语句子语法问题如下: