x^-3n=6 x^6n=?i

x^-3n=6 x^6n=?i 已知集合P={x|x=2n,n∈N^+},集合Q={x|x=3n,n∈N*}.则P∩Q等于多少?,A,{x|x=n,n∈N*}B.{x|x=5n,n∈N*}C,{x|x=12n,n∈N*}D,{x|x=6n,n∈N*} N={x| |x/i| 若x^3n=2,试求x^6n+x^4n乘以x^5n的值 x的^3n=2,求x^6n+x^4n*x^5n的值 已知x^3n=2 ,求 x^6n+x^2n*x^10n 的值. 计算:(2x^3n)(2x^n)^3=2x^6n 若x^2n=4,求x^6n和(3x^3n)^2 (6x^2n-24)/[x^(2n+3)+6x^(n+3)+9x^3]×(x^n+3)/(x^n-2)÷(3x^n+6)/[x^(n+2)+3x^2]哪位大虾会的= =(6x^2n-24)/[x^(2n+3)+6x^(n+3)+9x^3]×(x^n+3)/(x^n-2)÷(3x^n+6)/[x^(n+2)+3x^2]不知道哪根葱能出出这么令人吐血的题目! 为什么m = 9呢?# includeint main(void){int x;int i = 3;x = ((i++),(i++),(i++));printf(x=%d,i=%d ,x,i);int m;int n = 3;m = (n++)+(n++)+(n++);printf(m=%d,n=%d ,m,n);return 0;}x=5,i=6m=9,n=6Press any key to continue 若x^m=6,x^n=9,则(2x^3m*x^2n) / (x^m*x^n)^2*x^n N={x||x-1/i| N={x||x-1/i| N={x||x-1/i| 集合N={x||x/i| 已知x^m=3,x^n=6 求 x^m-n,x^3m-2n的值 X=[X;fliplr(x(i:2*N+i))] 设f(x)=(x-2^n+1)ln(x-2^n+1)-x(n属于n+),求证f(x)>=3sn+/6sn-2