求sin^2α+sin^2(π/3 +α)+sin^2(π/3 -α)

求sin^2α+sin^2(π/3 +α)+sin^2(π/3 -α) 化简sin(α+β)+sin(α-β)+2sinαsin(3π/2-β)= sin(π-α)=-2sin(π/2+α),求sinα·cosα sinα=-2cosα,求sin^2α-3sinαcosα+1 已知sin(α+β)*sin(α-β)=-1/3,求sin^2α-sin^2β的值 sinα+sinβ=1/3 求sinα-(cosβ）^2最大值 若(sinα+cosα)/(sinα-cosα)=2,求sin(α-5π)sin(3π/2-α)的值 已知sinα=-3sinα.求①(sinα+2cos)/(2sinα-cosα).②(sinα^2)-(3cosα^2)+1 已知3sinα cosα=0,求 3cosα 5sinα/sinα-cosα与sin²α 2sinα sin(α+β)=2/3,sin(α-β)=3/5,sinα+sinβ=1/2,求cos(α+β)/2*sin(α-β)/2 已知：3sin^2α+2sin^2β=2sinα,求sin^2α+sin^2β的值 已知3sin^2α—2sinα+2sin^2β=0 求sin^2α+sin^2β的取值范围 已知3sin^2α+2sin^2β=2sinα,求sin^2α+sin^2β的值 若 3sin^2α +2sin^2β =2sinα 求y=sin^2α+sin^2β的最大值 已知3(sinα)^2-2sinα+2(sinβ)^2=0,试求(sinα)^2+(sinβ)^2的取值范围 已知3sin^2α+sin^2β=2sinα,求sin^2α+sin^2β的最大值 已知3sin²α-2sinα+2sin²β=0,试求sin²α+sin²β的取值范围. 【数学题】已知3sin²α+2sin²β=2sinα,求sin²α+sin²β的取值范围