[-B1] While listening to pop music,________.A.she felt asleepB.the light went outC.someone knocked at the doorD.and she couldn't help laughing

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[-B1]Whilelisteningtopopmusic,________.A.shefeltasleepB.thelightwentoutC.someoneknockedatthedoorD.an

[-B1] While listening to pop music,________.A.she felt asleepB.the light went outC.someone knocked at the doorD.and she couldn't help laughing
[-B1] While listening to pop music,________.
A.she felt asleep
B.the light went out
C.someone knocked at the door
D.and she couldn't help laughing

[-B1] While listening to pop music,________.A.she felt asleepB.the light went outC.someone knocked at the doorD.and she couldn't help laughing
翻译：当（她）听流行音乐的时候,她睡着了.
1.此题考查状语从句的省略,该语法规定如下：如果状语从句的主语和主句主语一样,且从句谓语含有be动词时,可以把从句的主语和be动词一起省略.
即：while listening to pop music = while + (主句主语 + be动词) + listening to pop music.
2.很明显,这就要求主语主语必须是sb,而不能是sth,因为它有一个“listen to pop music”的动作.
由此排除用sth作主语的答案B；
3.C的主语someone虽然也是sb,但是句意不通：“当某个人听流行音乐的时候,这个人还在敲门”,排除C.
4.D更错得离谱,while引导一个时间状语从句,后面的主语居然又用连词and引导.
楼主应该知道：主从复合句的连词只能用一个,比如because/so,although/but不能连用.
所以正确答案为A.

简单地说，就是前后主语必须得保持一致。
发出listen这个动作的是she，而且中间有逗号，不用and

Ain't nobody listenin' today.listenin' 还有类似的用法吗? main(){char b1[8]=abcdefg,b2[8],*pb=b1+3; while(--p>=b1)strcpy(b2,pb);printf(%d,strlen(b2));}求结果,劳驾对不起打错了,是while(--pb>=b1) while(! while while(! while how can you expect to learn everything__you never listenin caseeven if unlessthougheverything改为anything [-B1] While listening to pop music,________.A.she felt asleepB.the light went outC.someone knocked at the doorD.and she couldn't help laughing She is used to music before she goes to bed 选择a .listen b.listen to c,listenin to 为什么 请高手分析一下句子成分:I like listeing to pop music.此处为啥用listenin↗g 请教一道C语言指针题!线上等!以下程序的输出结果是?#include main(){char b1[8]=abcdefg,b2[8],*pb=b1+3;while(--pb>=b1) strcpy(b2,pb);printf(%d ,strlen(b2));}麻烦请详细的写出解题思路, b1是什么意思 matlab dijkstra算法的问题,只能只能循环到第二步,%X是加权邻接举证distance1=ones(1,154)*inf;path1=ones(1,154)*63;B1=X(63,:);i=1;j=1;while j matlab三维plot3用法这道程序是我从别人那里借鉴过来的,所以读不懂,function M02K=1; （1.这里啊,定义的函数M02,后面K=1是有什么用的呢）%三维坐标变换hold onfor i=1:100a1=1;b1=1;while a1*a1+b1*b1> 1a=2*pi*rand while((i while(i do while while i