帮忙解答一题全英文的工程科学题Determine the behavior of dynamic mechanical systems in which uniform acceleration is present.The mining car filled with iron ore weights 1000～1500kg together and was pushed from Point G to Point F.The c
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帮忙解答一题全英文的工程科学题Determine the behavior of dynamic mechanical systems in which uniform acceleration is present.The mining car filled with iron ore weights 1000～1500kg together and was pushed from Point G to Point F.The c
帮忙解答一题全英文的工程科学题
Determine the behavior of dynamic mechanical systems in which uniform acceleration is present.The mining car filled with iron ore weights 1000～1500kg together and was pushed from Point G to Point F.The car starts with the velocity of 0.The friction factor of the car and the rail μ = 0.1.In the diagram 1,w=3m,h2=0.5m.Please determine the acceleration (a) of the car and the time (t) that the car uses to get to Point F.
帮忙解答一题全英文的工程科学题Determine the behavior of dynamic mechanical systems in which uniform acceleration is present.The mining car filled with iron ore weights 1000～1500kg together and was pushed from Point G to Point F.The c
翻译：动态机械系统的行为中,假设存在统一的加速.采矿车装满铁矿石的重量是1000〜1500kg,并从G点F点,初速度为0.汽车的摩擦系数和铁路μ= 0.1.在图中W= 3m,h= 0.5m.请确定汽车的加速度a和车到达F点所用的时间（t）
这是很简单的物理题哈
首先计算出斜边的长,为3.041m,这样就可以计算正弦和余弦值了!
然后计算重力G在垂直斜面的方向的分力F1=G*余弦值=1500*10*3/3.041=14797.8N
平行斜面的分力F2=1500*10*0.5/3.041=2466.3N
这样就可以计算加速度了,m*a=m*gsinA-m*gcosA*0.1,即
a=g*sinA-0.1g*cosA=0.653
然后计算时间
1/2a*t^2=3.041
所以t=3.05秒
设角a为GF与地面夹角.sin(a)=1/6
加速度=g*(sina-0.1cosa)
时间=6除以加速度的商的平方根.
开始的那个答案不对，摩擦力应该与平行斜面的重力分力的方向相反，所以m*a=m*gsinA-m*gcosA*0.1,
a=g*sinA-0.1g*cosA=0.658
然后计算时间
1/2a*t^2=3.041
所以t=3.04秒
希望能帮到你！