p1&=~(1

P1^0 = 0 ; P1^1 p1&=~(1 P1>>=1 已知Mov p1,#11H Setb p1.1 Clr p1.0 ,那么P1=? p1=p1->next p2=p1+strlen(p1)-1是什么意思啊? double p1 = 3.1415926;write(1,&p1,sizeof(p1));//如何输出小数? #includevoid main(){int *p1,*p2,a[5]={1,3,5,7,9};for(p1=a;p1 matlab 求解参数方程我解的是如下方程,其中P1,Xt,Yt都是已知的参数x1=solve('p1(1)^2*x1^2/Xt^2-p1(1)*p1(2)*x1^2/Xt^2+p1(2)^2*x1^2/Yt^2-1','x1')x1 =1/(p1(1)^2*Yt^2-p1(1)*p1(2)*Yt^2+p1(2)^2*Xt^2)^(1/2)*Yt*Xt-1/(p1(1)^2*Yt^2-p1(1)*p1(2 p1+p2+p3+p4=1 0 COLUMN(D1:F1) EXCL函数,=MAX(FREQUENCY(IF(A1:P1=1,COLUMN(A1:P1)),IF(A1:P1=1,COLUMN(A1:P1)))) void main() { int i=50,j=60,*p1=&i,*p2=&j; *p1++; printf(%d ,*p1); (*p1)++; printf(%d ,*p1);为什么不是书上的60,61呢,是不是哪里出错了?void main(){int ARRAY[]={50,60};int *p1=&ARRAY[0],*p2=&ARRAY[1];*p1++;printf(%d ,*p1);(*p1) P1=0x7F; for(i=0;i>=1; P1 |=0x80; } while(1) { temp=P1>>4; temp=temp | 0xf0; P1=temp; } sbit key1 = p1^0; sbit key2 = p1^1; sbit key3 = p1^2; sbit key4 = p1^3; sbit fmq=p2^1;sbit key1 = p1^0;sbit key2 = p1^1;sbit key3 = p1^2;sbit key4 = p1^3;sbit fmq=p2^1; void fun(char *w,int m) {char s,*p1,*p2;p1=w;p2=w+m-1;#include#includevoid fun (char*w,int m){char s,*p1,*p2;p1=w;p2=w+m-1;while(p1 while(*p1) p1++; while(*p2) { *p1=*p2; p1++; p2++; } *p1=0; 这个怎么理解啊?void fun(char p1[],char p2[]){while(*p1) p1++;while(*p2){*p1=*p2;p1++;p2++;}*p1=0;} p1=p2;p1->next!=NULL;p1=p1->next