f(x)=e^x/(x-1)对x求导

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f(x)=e^x/(x-1)对x求导f(x)=e^x/(x-1)对x求导f(x)=e^x/(x-1)对x求导一般的[f(x)/g(x)]''=[f''(x)g(x)-f(x)g''(x)]/[g^2(x)]

f(x)=e^x/(x-1)对x求导
f(x)=e^x/(x-1)对x求导

f(x)=e^x/(x-1)对x求导
一般的 [f(x)/g(x)]'=[f'(x)g(x)-f(x)g'(x)]/[g^2(x)]
所以对本题目f'(x)=[e^x*(x-1)-e^x*1]/(x-1)^2=e^x*(x-2)/(x-1)^2