2x^2-5x+m/1的值恒为正数,求m

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2x^2-5x+m/1的值恒为正数,求m2x^2-5x+m/1的值恒为正数,求m2x^2-5x+m/1的值恒为正数,求mm>25/85^2-4*2*(1/m)25-8/m8/m>25(8/m)*m^2

2x^2-5x+m/1的值恒为正数,求m
2x^2-5x+m/1的值恒为正数,求m

2x^2-5x+m/1的值恒为正数,求m
m>25/8

5^2-4*2*(1/m)<0
25-8/m<0
8/m>25
(8/m)*m^2>25*m^2
25m^2-8m<0
0

2x^2-5x的最小值为-25/8, 所以只要1/m>-25/8