1/(x2-2xy+y2)+1/(x2+2xy+y2)=1.那位懂的帮帮忙.

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1/(x2-2xy+y2)+1/(x2+2xy+y2)=1.那位懂的帮帮忙.1/(x2-2xy+y2)+1/(x2+2xy+y2)=1.那位懂的帮帮忙.1/(x2-2xy+y2)+1/(x2+2xy+

1/(x2-2xy+y2)+1/(x2+2xy+y2)=1.那位懂的帮帮忙.
1/(x2-2xy+y2)+1/(x2+2xy+y2)=1.那位懂的帮帮忙.

1/(x2-2xy+y2)+1/(x2+2xy+y2)=1.那位懂的帮帮忙.
1/(x2-2xy+y2)+1/(x2+2xy+y2)
=1/(x-y)2+1/(x+y)2
=(x+y)2/(x-y)2(x+y)2+(x-y)2/(x-y)2(x+y)2
=[(x+y)2+(x-y)2]/(x-y)2(x+y)2
=2(x2+y2)/(x2-y2)2
这个式子不是恒等式

题目写错了，你取x=2，y=1就是反例

2xy-x2+1-y2因式分解 x2-2xy+y2-1分解因式 1-x2-2xy-y2分解因式分解因式1-x2+2xy-y2 解方程组 x2 -2xy -y2 =1 2x2 -5xy -3y2 =0 解方程组 x2+2xy+y2-4=0 x2-2xy+y2-1=0 分解因式：1、a2b2-0.01 2、-xy-x2-y2 3、x2-xy+四分之一y2 已知x2+4y2+x2y2+1=6xy,则(x4-y4)/(2x2+xy-y2)*(2x-y)/(xy-y2)/(x2+y2/y)2= 解方程(x2+y2)2+1=x2+y2+2xy 解方程组：｛x2+y2=13,x2-2xy+y2=1要完整过程！！！~~ 因式分解x2+y2-xy-x-y+1 x2+y2-x2y2-4xy-1 x2+y2-x2y-4xy-1因式分解解方程组｛3x2-y2=8 {4x2+12xy+9y2=1 {x2+2xy+y2-4=0 x2+xy+y2=4 4x2-9y2=0 x2-2xy+y2-1=0还有{x2+y2=4xy-y2+4=0x2-----x的平方 y2------y的平方还有{2x-3y=12x2-3xy+y2-4x+3y-3=0 (x2+2xy+y2)( x2-xy+y2)2 化简 (x2-2xy+y2)-(x2+2xy+y2)=什么 ( x2+xy+y2) ( x2+xy+2y2)-12y4 x2-2xy+y2-1/x-y-1