1.若(a+b)^2=40,(a-b)^2=60,则a^2+b^2=( ) ab=( )1(2x+3y+1)(2x-3y+1)-(2x-3y-1) 2(x-2)^2(x+2)^2(x^2+4)^23(1+2)(1+2^2)(1+2^4)...(1+2^2012)4[2x^2-(x+y)(x-y)][(2-x)(x+2)+(-y-2)(2+y)]其中x.y满足代数式4x^2+9y^2
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1.若(a+b)^2=40,(a-b)^2=60,则a^2+b^2=( ) ab=( )1(2x+3y+1)(2x-3y+1)-(2x-3y-1) 2(x-2)^2(x+2)^2(x^2+4)^23(1+2)(1+2^2)(1+2^4)...(1+2^2012)4[2x^2-(x+y)(x-y)][(2-x)(x+2)+(-y-2)(2+y)]其中x.y满足代数式4x^2+9y^2
1.若(a+b)^2=40,(a-b)^2=60,则a^2+b^2=( ) ab=( )
1(2x+3y+1)(2x-3y+1)-(2x-3y-1)
2(x-2)^2(x+2)^2(x^2+4)^2
3(1+2)(1+2^2)(1+2^4)...(1+2^2012)
4[2x^2-(x+y)(x-y)][(2-x)(x+2)+(-y-2)(2+y)]其中x.y满足代数式4x^2+9y^2-4x+12y-1取最小值时的x,y的取值
1.若(a+b)^2=40,(a-b)^2=60,则a^2+b^2=( ) ab=( )1(2x+3y+1)(2x-3y+1)-(2x-3y-1) 2(x-2)^2(x+2)^2(x^2+4)^23(1+2)(1+2^2)(1+2^4)...(1+2^2012)4[2x^2-(x+y)(x-y)][(2-x)(x+2)+(-y-2)(2+y)]其中x.y满足代数式4x^2+9y^2
标题:50,-5
1:(2x-1/2)^2-(3y+1/2)^2
2:X^8-32X^4+256
3:这个题应该是出错了吧,题目最后应该是1+2^2048,这样的话正确结果应该是2^4096-1
4:x=0.5,y=-2/3,结果自己带进去算吧