a1=2 an+1/an=n/n+1 求an 为什么数列{nan}是各项均等于2的常数数列.a(n+1)/an=n/(n+1 )

数列｛an},a1=1,an+1=2an-n^2+3n,求｛an｝. 数列{an}中,a1=1,an+1/an=n/n+2,求an 数列{An}满足a1=1/2,a1+a2+..+an=n方an,求an a1=1,Sn=n^2an,求an 已知A1=1,An=2An-1+n（n>1）,求An. 数列an满足a1=1/3,Sn=n(2n-1)an,求an 数列{an},a1=3,an*a(n+1)=(1/2)^n,求an 数列{an}满足a1=2,a(n+1)=2an+n+2,求an a1=5,n大于等于2时,an-an-1=6n,求an 已知数列｛an｝中,a(n+1)=an+2^n,a1=3,求an 已知数列an中,a1=1,an/an-1=n+1/n,n大于等于2,求an an+1 ,n+1是下表 ,an+1=an^3 a1=2 ,求an a1=1/2,an+1=an/an+2,求n/an的sn 数列an集合中,a1=2,an+1=an+(2n+1),求an. 数列{an}中,a1=35,an+1-an=2n-1,求an 数列｛an｝满足a1=1,且an=an-1+3n-2,求an 已知数列{an}满足an+1=2an+3.5^n,a1=6.求an 已知{an}满足a1=1.an=3*n+2An-1,求an