-1/12+(0.3*10/3+1/3)*4
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-1/12+(0.3*10/3+1/3)*4-1/12+(0.3*10/3+1/3)*4-1/12+(0.3*10/3+1/3)*4
-1/12+(0.3*10/3+1/3)*4
-1/12+(0.3*10/3+1/3)*4
-1/12+(0.3*10/3+1/3)*4
-1/12+(0.3*10/3+1/3)*4
—1/12+(0.3×10/3+1/3)÷‖-4‖
-1/12+(0.3+10/9+1/3)÷|-4|过程
-1/12+(0.3×2/3+1/3)÷|-4|
上面写不下,我写在下面填符号1.(1)1/2( )0.4( )3/10( )0.1=1 (2)1/2( )0.4( )3/10( )1/5( )0.1( )=10 2.(1)0.3( )0.3( )0.3( )0.3( )0.3=0 (2)0.3( )0.3( )0.3( )0.3( )0.3=1 (3)0.3( )0.3( )0.3( )0.3( )0.3=2 (4)0.3( )0.3( )0.3( )0.3( )0.3=4 3.(1)0
[79×(1/3+0.72)-0.3]×(1/10-0.1)
按运算结果的要求,添上运算符号和括号 1/2 0.4 3/10 1/5 0.1=10 0.3 0.3 0.3 0.3 0.3=00.3 0.3 0.3 0.3 0.3=10.3 0.3 0.3 0.3 0.3=20.3 0.3 0.3 0.3 0.3=4
-12分之1+(0.3乘以3又3分之1+3分之1)除以(-4)
3.5÷1又3分之1+6.5×[12×(1又3分之1-0.3)-0.15]
1/3和0.3.为什么?
10^3+(1/30)^-2*(-7)^0-(-3)^3*0.3^-1+|-14|
( ):12=1/4:1/3=0.3/( )=12/( )=( )%
3-5/6+1 又7/12+3-1 又1/4 1+[(2又2/3-0.3)-(0.3+2/3)] 能简算的简算
4【2x-1]-2[10x+1]=3[2x+1]-12 0.3x+0.7[200-x]=108
1/3是否等于0.3 3循环
3.5÷1又1/3+6.5×[12×(1又1/3-0.3)-15%]急
为什么1/3×3=1,而1/3=0.3...,0.3...×3=0.9...?
-1|12+(0.3*三又三分之一+1|3)除以负四的绝对值