一道一元一次方程,[100x+10(x-2)+24-x-(x-2)]-(10x+x)=100[24-x-(x-2)]+10(x-2)+x[100x+10(x-2)+24-x-(x-2)]-(10x+x)=100[24-x-(x-2)]+10(x-2)+x
来源：学生作业帮助网 编辑：六六作业网 时间：2024/11/23 23:22:12
一道一元一次方程,[100x+10(x-2)+24-x-(x-2)]-(10x+x)=100[24-x-(x-2)]+10(x-2)+x[100x+10(x-2)+24-x-(x-2)]-(10x+x)=100[24-x-(x-2)]+10(x-2)+x
一道一元一次方程,[100x+10(x-2)+24-x-(x-2)]-(10x+x)=100[24-x-(x-2)]+10(x-2)+x
[100x+10(x-2)+24-x-(x-2)]-(10x+x)=100[24-x-(x-2)]+10(x-2)+x
一道一元一次方程,[100x+10(x-2)+24-x-(x-2)]-(10x+x)=100[24-x-(x-2)]+10(x-2)+x[100x+10(x-2)+24-x-(x-2)]-(10x+x)=100[24-x-(x-2)]+10(x-2)+x
先去小括号 [100x+10x-20+24-x-x+2]-11x=100[24-x-x+2]+x
合并同类项 [108x+6]-11x=100[24-2x]+x
去大括号 108x+6-11x=2400-200x+x
合并同类项 97x+6=2400-199x
移向 97x+199x=2400-6
合并同类项 286x=2574
x=9
100x+10x-20+24-x-x+2-11x=100(24-x-x+2)+10x-20+x
97x+6=2600-200x+11x-20
286x=2574
x=9
100x+10x-20+24-x-x+2-11x=100(24-x-x+2)+10x-20+x
97x+6=2600-200x+11x-20
286x=2574
x=9
(100x+10x-20+24-x-x+2)-11x=100(24-2x+2)+10x-20+x
108x+6-11x=100(26-2x)+11x-20
97x+6=2600-200x+11x-20
97x+6=2580-189x
97x+189x=2580-6
256x=2574
x约等于10
（错了就算了哦）