2-(2x-4)/3=(x-7)/6

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2-(2x-4)/3=(x-7)/62-(2x-4)/3=(x-7)/62-(2x-4)/3=(x-7)/6两边同时乘以6得:12-2(2x-4)=x-712-4x+8=x-720-4x=x-74x+

2-(2x-4)/3=(x-7)/6
2-(2x-4)/3=(x-7)/6

2-(2x-4)/3=(x-7)/6
两边同时乘以 6 得:
12 - 2(2x - 4) = x - 7
12 - 4x + 8 = x - 7
20 - 4x = x - 7
4x + x = 20 + 7
5x = 27
x = 27 ÷ 5
x = 5.4

X=5.4

x=27/5

2-(2x-4)/3=(x-7)/6
2-2x/3+4/3=x/6-7/6
2+4/3+7/6=x/6+2x/3
27/6=5x/6
5x=27
x=27/5
x=5.4

2-(2x-4)/3=(x-7)/6
12-4x+8=x-7(同时乘以6)
12+7+8=x+4x
27=5x
x=5/27

①将左边的（2x-4）/3移到右边得到2=(x-7)/6+(2x-4)/3；②左右两边同乘以6得到12=(x-7)+2(2x-4)即12=x-7+4x-8=5x-15；③12=5x-15得到5x=27即x=27/5；

2x6-(2x-4)/3x6=(x-7)/6x6
12-4x+8=x-7
20+7=5x
27/5=x

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